Re: Any honest person that knows the x86 language can see...

Liste des GroupesRevenir à ca philosophy 
Sujet : Re: Any honest person that knows the x86 language can see...
De : F.Zwarts (at) *nospam* HetNet.nl (Fred. Zwarts)
Groupes : comp.theory comp.ai.philosophy
Date : 29. Jul 2024, 21:38:57
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v88r4i$ju20$6@dont-email.me>
References : 1 2 3
User-Agent : Mozilla Thunderbird
Op 29.jul.2024 om 21:35 schreef olcott:
On 7/29/2024 2:18 PM, Fred. Zwarts wrote:
Op 29.jul.2024 om 16:07 schreef olcott:
HHH(Infinite_Recursion) and HHH(DDD) show the same non-halting
behavior pattern in their derived execution traces of their
inputs.
>
Correct emulation is defined as emulating the machine language
input according to the x86 semantics specified by this input.
>
For DDD correctly emulated by HHH this includes HHH emulating
itself emulating DDD according to the x86 semantics of itself.
>
HHH(DDD) shows the exact same execution trace behavior pattern
as HHH(Infinite_Recursion) where 3-4 instructions are repeated
with no conditional branch instructions in this trace that could
prevent them from endlessly repeating.
>
void Infinite_Recursion()
{
   Infinite_Recursion();
}
>
No, the HHH that aborts after N cycles has a similar behaviour as
>
 So you don't even know that infinite recursion is non-halting behavior.
You can go back and try again on this same post I am not looking at
anything else that you say.
Non halting is only in your dreams. HHH that aborts halts. Dreams are no substitute for logic.

Date Sujet#  Auteur
29 Jul 24 * Any honest person that knows the x86 language can see...7olcott
29 Jul 24 +* Re: Any honest person that knows the x86 language can see...5Fred. Zwarts
29 Jul 24 i`* Re: Any honest person that knows the x86 language can see...4olcott
29 Jul 24 i `* Re: Any honest person that knows the x86 language can see...3Fred. Zwarts
29 Jul 24 i  `* Re: Any honest person that knows the x86 language can see...2olcott
30 Jul 24 i   `- Re: Any honest person that knows the x86 language can see...1Fred. Zwarts
30 Jul 24 `- Re: Any honest person that knows the x86 language can see... DDD will HALT if HHH answers1Richard Damon

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