Re: How many different unit fractions are lessorequal than all unit fractions? (repleteness)

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Sujet : Re: How many different unit fractions are lessorequal than all unit fractions? (repleteness)
De : james.g.burns (at) *nospam* att.net (Jim Burns)
Groupes : sci.math
Date : 16. Sep 2024, 20:13:04
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <a8b5743b-1bcf-49c1-936b-c4e92af9dec4@att.net>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
User-Agent : Mozilla Thunderbird
On 9/15/2024 9:31 PM, Ross Finlayson wrote:
On 09/15/2024 03:07 PM, FromTheRafters wrote:
on 9/15/2024, Ross Finlayson supposed :
On 09/15/2024 11:03 AM, FromTheRafters wrote:
After serious thinking Ross Finlayson wrote :

"What, no witty rejoinder?"
>
What you said has no relation to
the 'nextness' of elements in discrete sets.
What is 'next' to Pi+2 in the reals?
>
In the, "hyper-reals", it's its neighbors,
in the line-reals, put's previous and next,
in the field-reals, there's none,
and in the signal-reals, there's nothing.

What is the successor function on the reals?
Give me that, and maybe we can find the
'next' number greater than Pi.
>
Ah, good sir, then I'd like you to consider
a representation of real numbers as
with an integer part and a non-integer part,
the integer part of the integers, and
the non-integer part a value in [0,1],
where the values in [0,1], are as of
this model of (a finite segment of a) continuous domain,
these iota-values, line-reals,
as so established as according to the properties of
extent, density, completeness, and measure,
fulfilling implementing the Intermediate Value Theorem,
thus for
if not being the complete-ordered-field the field-reals,
yet being these iota-values a continuous domain [0,1]
these line-reals.
As n → ∞, (ι=⅟n), ⟨0,ι,2⋅ι,...,n⋅ι⟩ → ℚ∩[0,1]
ℚ∩[0,1] is not complete.
ℚ∩[0,1] has one connected component,
being what you (RF) call "continuous".
ℚ∩[0,1] has no points next to each other.

I wonder what you think of something like Hilbert's
"postulate of continuity" for geometry, as with
regards to that in the course-of-passage of
the growth of a continuous quantity, it encounters,
in order, each of the points in the line.
That sounds like the Intermediate Value Theorem,
where "encounters each" == 'no skips".
The Intermediate Value Theorem
is equivalent to
Dedekind completeness.

Date Sujet#  Auteur
21 Sep 24 o 

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