Sujet : THREE DIFFERENT QUESTIONS
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theory sci.logicDate : 19. Oct 2024, 01:52:57
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <veuvt9$3hnjq$1@dont-email.me>
References : 1 2 3 4 5 6 7 8
User-Agent : Mozilla Thunderbird
On 10/18/2024 6:06 PM, Richard Damon wrote:
On 10/18/24 10:10 AM, olcott wrote:
On 10/18/2024 6:17 AM, Richard Damon wrote:
On 10/17/24 11:47 PM, olcott wrote:
On 10/17/2024 10:27 PM, Richard Damon wrote:
On 10/17/24 9:47 PM, olcott wrote:
On 10/17/2024 8:13 PM, Richard Damon wrote:
On 10/17/24 7:31 PM, olcott wrote:
_DDD()
[00002172] 55 push ebp ; housekeeping
[00002173] 8bec mov ebp,esp ; housekeeping
[00002175] 6872210000 push 00002172 ; push DDD
[0000217a] e853f4ffff call 000015d2 ; call HHH(DDD)
[0000217f] 83c404 add esp,+04
[00002182] 5d pop ebp
[00002183] c3 ret
Size in bytes:(0018) [00002183]
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When DDD is correctly emulated by HHH according
to the semantics of the x86 language DDD cannot
possibly reach its own machine address [00002183]
no matter what HHH does.
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+-->[00002172]-->[00002173]-->[00002175]-->[0000217a]--+
+------------------------------------------------------+
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That may not line up that same way when view
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https://en.wikipedia.org/wiki/State_diagram
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Except that 0000217a doesn't go to 00002172, but to 000015d2
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IS THIS OVER YOUR HEAD?
What is the first machine address of DDD that HHH
emulating itself emulating DDD would reach?
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Yes, HHH EMULATES the code at that address,
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Which HHH emulates what code at which address?
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Everyone, just once, which you should know, but ignore.
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The Emulating HHH sees those addresses at its begining and then never again.
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Then the HHH that it is emulating will see those addresses, but not the outer one that is doing that emulation of HHH.
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Then the HHH that the second HHH is emulating will, but neither of the outer 2 HHH.
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And so on.
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Which HHH do you think EVER gets back to 00002172?
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What instruction do you think that it emulates that would tell it to do so?
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It isn't the call instruction at 0000217a, as that tells it to go into HHH.
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At best the trace is:
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00002172
00002173
00002175
0000217a
conditional emulation of 00002172
conditional emulation of 00002173
conditional emulation of 00002175
conditional emulation of 0000217a
CE of CE of 00002172
...
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OK great this is finally good progress.
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The "state" never repeats, it is alway a new state,
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Every emulated DDD has an identical process state at every point
in its emulation trace when adjusting for different top of stack values.
Nope, remember, each of those levels are CONDITIONAL,
*There are THREE different questions here*
(1) Can DDD emulated by HHH according to the semantics
of the x86 language possibly reach its machine address
[00002183] no matter what HHH does?
(2) Does HHH correctly detect and report the above?
(3) Does HHH do (2) it as a Turing computable function?
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer