Re: Parsing timestamps?

On 06/10/2024 08:51, dxf wrote:

Is there an easier way of doing this?  End goal is a double number representing centi-secs.
  empty decimal
 : SPLIT ( a u c -- a2 u2 a3 u3 )  >r 2dup r> scan 2swap 2 pick - ;
: >INT ( adr len -- u )  0 0 2swap >number 2drop drop ;
 : /T ( a u -- $hour $min $sec )
   2 0 do  [char] : split  2swap  dup if 1 /string then  loop
   2 0 do  dup 0= if 2rot 2rot then  loop ;
 : .T  2swap 2rot  cr  >int . ." hr "  >int . ." min " >int . ." sec " ;
 s" 1:2:3"    /t .t
s" 02:03"    /t .t
s" 03"       /t .t
s" 23:59:59" /t .t
s" 0:00:03"  /t .t

Another solution
: /t  ( ca u -- sec min hour )
    3        \ a count, decremented every recurse
    [: -rot dup 0>
       if 0. 2swap >number 1 /string 2swap drop ( -- ct ca' u' n1 )
          >r rot 1-
          recurse r> swap exit
       then 2drop
    ;] execute
    0 ?do 0 loop   \ 0 hours and minutes if missing in source string
;
: .t   cr . ." hr "  . ." min " . ." sec " ;
cr
s" 1:2:3"    /t .t
s" 02:03"    /t .t
s" 03"       /t .t
s" 23:59:59" /t .t
s" 0:00:03"  /t .t
s" " /t .t
s" :" /t .t
s" :53" /t .t
s" 11/12/13" /t .t   \ Different separator
s" 11::13" /t .t
s" :::" /t .t
s" 3:" /t .t
s" 1:2:" /t .t
\ Results
1 hr 2 min 3 sec
0 hr 2 min 3 sec
0 hr 0 min 3 sec
23 hr 59 min 59 sec
0 hr 0 min 3 sec
0 hr 0 min 0 sec
0 hr 0 min 0 sec
0 hr 0 min 53 sec
11 hr 12 min 13 sec
11 hr 0 min 13 sec
0 hr 0 min 0 sec
0 hr 0 min 3 sec
0 hr 1 min 2 sec
The last two could be regarded as wrong but you indicated elsewhere that they wouldn't occur.
Any non-digit is a separator
--
Gerry