Re: Parsing timestamps?

On 29/10/2024 4:07 am, Hans Bezemer wrote:

...
I have put the complication elsewhere. If we assume we're working in decimal, you don't even need >NUMBER:
 
char 0 negate +constant 0-
 
: /int    ( a1 n1 -- a2 n2 n3)
  0 >r 1 >r 1- chars over +
  begin
   over 1- over <
  while
    dup c@ is-digit
  while
    dup c@ 0- r> tuck * r> + >r 10 * >r 1-
  repeat over - rdrop r> -rot
;
...

So that's how to convert a numeric string from the other end.
Nice!  Easier than I imagined it would be.