Re: Parsing timestamps?

On 7/06/2025 10:38 pm, B. Pym wrote:

mhx wrote:
 

On Sun, 6 Oct 2024 7:51:31 +0000, dxf wrote:
>

Is there an easier way of doing this?  End goal is a double number
representing centi-secs.
>
>
empty decimal
>
: SPLIT ( a u c -- a2 u2 a3 u3 )  >r 2dup r> scan 2swap 2 pick - ;
: >INT ( adr len -- u )  0 0 2swap >number 2drop drop ;
>
: /T ( a u -- $hour $min $sec )
 2 0 do  [char] : split  2swap  dup if 1 /string then  loop
 2 0 do  dup 0= if 2rot 2rot then  loop ;
>
: .T  2swap 2rot  cr  >int . ." hr "  >int . ." min " >int . ." sec " ;
>
s" 1:2:3"    /t .t
s" 02:03"    /t .t
s" 03"       /t .t
s" 23:59:59" /t .t
s" 0:00:03"  /t .t

>
Why don't you use the fact that >NUMBER returns the given
string starting with the first unconverted character?
SPLIT should be redundant.
>
-marcel

 
: CHAR-NUMERIC?   48 58 WITHIN ;
: SKIP-NON-NUMERIC ( adr u -- adr2 u2)
  BEGIN
    DUP IF  OVER C@ CHAR-NUMERIC? NOT  ELSE  0 THEN
  WHILE
    1 /STRING
  REPEAT ;
 
: SCAN-NEXT-NUMBER ( n adr len -- n2 adr2 len2)
  2>R  60 *  0.  2R> >NUMBER 
  2>R  D>S +  2R> ;
 
: PARSE-TIME  ( adr len -- seconds)
  0 -ROT
  BEGIN
    SKIP-NON-NUMERIC
    DUP
  WHILE
    SCAN-NEXT-NUMBER
  REPEAT
  2DROP ;
 
S" hello 1::36 world" PARSE-TIME CR .
96  ok

Does more than I needed.  But shouldn't the result be 3636 ?