Re: True on the basis of meaning --- Good job Richard ! ---Socratic method

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Sujet : Re: True on the basis of meaning --- Good job Richard ! ---Socratic method
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : sci.logic
Date : 19. May 2024, 15:15:51
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v2d1io$3dplm$1@dont-email.me>
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User-Agent : Mozilla Thunderbird
On 5/19/2024 9:03 AM, Mikko wrote:
On 2024-05-19 13:41:56 +0000, olcott said:
 
On 5/19/2024 6:55 AM, Richard Damon wrote:
On 5/18/24 11:47 PM, olcott wrote:
On 5/18/2024 6:04 PM, Richard Damon wrote:
On 5/18/24 6:47 PM, olcott wrote:
On 5/18/2024 5:22 PM, Richard Damon wrote:
On 5/18/24 4:00 PM, olcott wrote:
On 5/18/2024 2:57 PM, Richard Damon wrote:
On 5/18/24 3:46 PM, olcott wrote:
On 5/18/2024 12:38 PM, Richard Damon wrote:
On 5/18/24 1:26 PM, olcott wrote:
On 5/18/2024 11:56 AM, Richard Damon wrote:
On 5/18/24 12:48 PM, olcott wrote:
On 5/18/2024 9:32 AM, Richard Damon wrote:
On 5/18/24 10:15 AM, olcott wrote:
On 5/18/2024 7:43 AM, Richard Damon wrote:
No, your system contradicts itself.
>
>
You have never shown this.
The most you have shown is a lack of understanding of the
Truth Teller Paradox.
>
No, I have, but you don't understand the proof, it seems because you don't know what a "Truth Predicate" has been defined to be.
>
>
My True(L,x) predicate is defined to return true or false for every
finite string x on the basis of the existence of a sequence of truth
preserving operations that derive x from
>
And thus, When True(L, p) established a sequence of truth preserving operations eminationg from ~True(L, p) by returning false, it contradicts itself. The problem is that True, in making an answer of false, has asserted that such a sequence exists.
>
On 5/13/2024 9:31 PM, Richard Damon wrote:
 > On 5/13/24 10:03 PM, olcott wrote:
 >> On 5/13/2024 7:29 PM, Richard Damon wrote:
 >>>
 >>> Remember, p defined as ~True(L, p) ...
 >>
 >> Can a sequence of true preserving operations applied
 >> to expressions that are stipulated to be true derive p?
 > No, so True(L, p) is false
 >>
 >> Can a sequence of true preserving operations applied
 >> to expressions that are stipulated to be true derive ~p?
 >
 > No, so False(L, p) is false,
 >
>
*To help you concentrate I repeated this*
The Liar Paradox and your formalized Liar Paradox both
contradict themselves that is why they must be screened
out as type mismatch error non-truth-bearers *BEFORE THAT OCCURS*
>
And the Truth Predicate isn't allowed to "filter" out expressions.
>
>
YOU ALREADY KNOW THAT IT DOESN'T
WE HAVE BEEN OVER THIS AGAIN AND AGAIN
THE FORMAL SYSTEM USES THE TRUE AND FALSE PREDICATE
TO FILTER OUT TYPE MISMATCH ERROR
>
The first thing that the formal system does with any
arbitrary finite string input is see if it is a Truth-bearer:
Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>
No, we can ask True(L, x) for any expression x and get an answer.
>
>
The system is designed so you can ask this, yet non-truth-bearers
are rejected before True(L, x) is allowed to be called.
>
>
>
>
Not allowed.
>
>
My True(L,x) predicate is defined to return true or false for every
finite string x on the basis of the existence of a sequence of truth
preserving operations that derive x from
>
A set of finite string semantic meanings that form an accurate
verbal model of the general knowledge of the actual world that
form a finite set of finite strings that are stipulated to have
the semantic value of Boolean true.
>
*This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
*This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
*This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
*This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
*This is computable* Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
>
>
>
So, for a statement x to be false, it says that there must be a sequence of truth perserving operations that derive ~x from, right?
>
Yes we must build from mutual agreement, good.
>
So do you still say that for p defined in L as ~True(L, p) that your definition will say that True(L, p) will return false?
>
>
It is the perfectly isomorphic to this:
True(English, "This sentence is not true")
>
>
>
Nope, Because "This sentece is not true" can be a non-truth-bearer, but by its definition, True(L, x) can not.
>
>
True(L,x) is always a truth bearer.
when x is defined as True(L,x) then x is not a truth bearer.
 When x is defined as True(L,x) then x is what True(L,x) is,
in this case a truth bearer.
 
This is known as the Truth Teller Paradox
*This is the best of the references that I found*
https://philosophy.stackexchange.com/questions/64138/logical-semantic-and-self-referential-paradoxes-the-truth-teller-and-the-liar
"This sentence is true" // is the truth teller paradox
TT := True(L,TT) // is the precisely formalized truth teller paradox
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

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