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On 6/1/24 1:27 PM, olcott wrote:*THEN TRY TO REFUTE THIS UNEQUIVOCAL STATEMENT*On 6/1/2024 12:22 PM, Richard Damon wrote:Why? I don't care about it.On 6/1/24 12:38 PM, olcott wrote:>On 6/1/2024 11:27 AM, Richard Damon wrote:>On 6/1/24 12:13 PM, olcott wrote:>On 6/1/2024 10:56 AM, Richard Damon wrote:>On 6/1/24 11:30 AM, olcott wrote:>>>
*I will not discuss any other points with you until after you either*
(a) Acknowledge that DD correctly simulated by HH and ⟨Ĥ⟩ ⟨Ĥ⟩ correctly
simulated by embedded_H remain stuck in recursive simulation for
1 to ∞ of correct simulation or
>
(b) Correctly prove otherwise.
And until you answer the question of what that actually means, I will reply WHO CARES.
>
typedef int (*ptr)(); // ptr is pointer to int function in C
00 int HH(ptr p, ptr i);
01 int DD(ptr p)
02 {
03 int Halt_Status = HH(p, p);
04 if (Halt_Status)
05 HERE: goto HERE;
06 return Halt_Status;
07 }
08
09 int main()
10 {
11 HH(DD,DD);
12 return 0;
13 }
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Every DD correctly simulated by any HH of the infinite set of HH/DD
pairs that match the above template never reaches past its own simulated
line 03 in 1 to ∞ steps of correct simulation of DD by HH.
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In this case HH is either a pure simulator that never halts or
HH is a pure function that stops simulating after some finite number
of simulated lines. The line count is stored in a local variable.
The pure function HH always returns the meaningless value of 56
after it stops simulating.
>
So, still no answer, to teh question.
You can pretend that you don't understand something that you do indeed
understand into perpetuity.
>
The key measure of dishonestly would be that you continue to say
that you don't understand yet never ever point out exactly what you
don't understand and why you don't understand it.
>I giuess that Mean YOU don't even know what you are asking, though it seems that now you are admitting that your HH doesn't actually ANSWER the question, so it isn't ACTUALL a decider for any function except the "56" mapping.>
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I will repeat the question and until you answer the question of what that actually means, I will reply WHO CARES.
>
DO you mean the simulation of the TEMPLATE DD,
*Of course I don't mean that nonsense. I mean exactly what I specified*
>which means that we CAN'T simulate the call HH as we have no code past point to simulate, and thus your claim is just a LIE.>
>
Or, do you mean a given instance of HH simulating a given instance of DD, at which point we never have the 1 to infinte number of simulatons of THAT INPUT, so your claim is just a LIE.
>
Every element of the infinite set of every H/D pairs...
Every element of the infinite set of every H/D pairs...
Every element of the infinite set of every H/D pairs...
>
*Its not that hard when one refrains from dishonesty*
We can't even say that you forgot these details from one reply
to the next because the details are still in this same post.
>
And every one gives a meaningless answer,
*THEN TRY TO REFUTE THIS UNEQUIVOCAL STATEMENT*
DD correctly emulated by HH with an x86 emulator cannot possibly
reach past its own machine instruction [00001c2e] in any finite
number of steps of correct emulation.
>
As I have said, the implication of your definition of "Correct SImulation" means that this says NOTHING about the halting behavior of DD. (only not halted yet)
--_DD()
[00001c22] 55 push ebp
[00001c23] 8bec mov ebp,esp
[00001c25] 51 push ecx
[00001c26] 8b4508 mov eax,[ebp+08]
[00001c29] 50 push eax ; push DD 1c22
[00001c2a] 8b4d08 mov ecx,[ebp+08]
[00001c2d] 51 push ecx ; push DD 1c22
[00001c2e] e80ff7ffff call 00001342 ; call HH
[00001c33] 83c408 add esp,+08
[00001c36] 8945fc mov [ebp-04],eax
[00001c39] 837dfc00 cmp dword [ebp-04],+00
[00001c3d] 7402 jz 00001c41
[00001c3f] ebfe jmp 00001c3f
[00001c41] 8b45fc mov eax,[ebp-04]
[00001c44] 8be5 mov esp,ebp
[00001c46] 5d pop ebp
[00001c47] c3 ret
Size in bytes:(0038) [00001c47]
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