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On 6/2/2024 5:20 PM, Richard Damon wrote:But the second line doesn't change the meaning of the first line, as Halting ALWAYS (unless clearly modified) refers to the behavior of the machine.On 6/2/24 6:05 PM, olcott wrote:*Deceitfully taking things out of context*On 6/2/2024 4:43 PM, Richard Damon wrote:>On 6/2/24 5:25 PM, olcott wrote:>On 6/2/2024 3:58 PM, Richard Damon wrote:>On 6/2/24 4:50 PM, olcott wrote:>*We can see that the following DD cannot possibly halt*>
Unless the HH(DD,DD) aborts its simulation and returns 0, then DD(DD) will ALWAYS halt when directly called, which is the definition of "Halting".
>
Not your LIE that it pertains to partial simulations.
>*when correctly simulated by every HH that can possibly exist*>
Except for EVERY HH that aborts its simulation and returns 0
>
This may be an ADD thing.
For every HH that aborts its simulation and returns 0
DD correctly simulated by this HH *DID NOT HALT AND NEVER WILL HALT*
Except you mental problems are getting in YOUR way.
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You said that "DD Can not halt" NOT "the simulation by H of DD can not Halt"
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*I said neither of those things so it may be an ADD problem*
I guess your medication is making you blind.
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Read the top line quoted from you on 6/2/24 4:50 PM
>
You said:
"*We can see that the following DD cannot possibly halt*"
>
On 6/2/2024 3:50 PM, olcott wrote:
> *We can see that the following DD cannot possibly halt*
> *when correctly simulated by every HH that can possibly exist*
So, if you ever slightmRemember, Halting is defined as the MACHINE reaching a fianl state, so trying to qualify it with a partial simulation is an irrelevent qualification.If you get my words 99.99999% perfectly then you screwed up
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>>>Those are DIFFERENT statements.>
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DD WILL Halt.
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Your claim, that I will neither confirm or deny (until you can show why I should), is that the simulation by H can never reach the statement after the call instruction.
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*Still not quite what I said*
But you did in your message from 3:54 today earier in the thread:
>
DD correctly emulated by HH with an x86 emulator cannot possibly
reach past its own machine instruction [00001c2e]
>
far too much, thus 80% is not in the ballpark.
*We can see that the following DD cannot possibly halt*Nope ABSOLUTE LIE.
*when correctly simulated by every HH that can possibly exist*
typedef int (*ptr)(); // ptr is pointer to int function in C
00 int HH(ptr p, ptr i);
01 int DD(ptr p)
02 {
03 int Halt_Status = HH(p, p);
04 if (Halt_Status)
05 HERE: goto HERE;
06 return Halt_Status;
07 }
_DD()
[00001c22] 55 push ebp
[00001c23] 8bec mov ebp,esp
[00001c25] 51 push ecx
[00001c26] 8b4508 mov eax,[ebp+08]
[00001c29] 50 push eax ; push DD 1c22
[00001c2a] 8b4d08 mov ecx,[ebp+08]
[00001c2d] 51 push ecx ; push DD 1c22
[00001c2e] e80ff7ffff call 00001342 ; call HH
[00001c33] 83c408 add esp,+08
[00001c36] 8945fc mov [ebp-04],eax
[00001c39] 837dfc00 cmp dword [ebp-04],+00
[00001c3d] 7402 jz 00001c41
[00001c3f] ebfe jmp 00001c3f
[00001c41] 8b45fc mov eax,[ebp-04]
[00001c44] 8be5 mov esp,ebp
[00001c46] 5d pop ebp
[00001c47] c3 ret
Size in bytes:(0038) [00001c47]
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