Re: D correctly simulated by H proved for THREE YEARS --- Richard admits his error

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Sujet : Re: D correctly simulated by H proved for THREE YEARS --- Richard admits his error
De : polcott333 (at) *nospam* gmail.com (olcott)
Groupes : comp.theory sci.logic
Date : 11. Jun 2024, 05:31:30
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v48jv2$se9c$1@dont-email.me>
References : 1 2 3 4
User-Agent : Mozilla Thunderbird
On 6/10/2024 10:32 PM, Richard Damon wrote:
On 6/10/24 10:06 PM, olcott wrote:
On 6/10/2024 6:16 AM, Richard Damon wrote:
On 6/9/24 11:54 PM, olcott wrote:
*No one has verified the actual facts of this for THREE YEARS*
*No one has verified the actual facts of this for THREE YEARS*
*No one has verified the actual facts of this for THREE YEARS*
>
So, I guess you are admitting that you claim it as a verified fact is just a LIE.
>
>
On 5/29/2021 2:26 PM, olcott wrote:
https://groups.google.com/g/comp.theory/c/dTvIY5NX6b4/m/cHR2ZPgPBAAJ
>
THE ONLY POSSIBLE WAY for D simulated by H to have the same
behavior as the directly executed D(D) is for the instructions
of D to be incorrectly simulated by H (details provided below).
>
So, I guess you are admitting that this means that "D correctly simulated by H" is NOT a possible equivalent statement for the behavior of the direct execution of the input as required by the Halting Problem, so you admit you have been LYING every time you imply that it is.
>
>
_D()
[00000cfc](01)  55                      push ebp
[00000cfd](02)  8bec                    mov ebp,esp
[00000cff](03)  8b4508                  mov eax,[ebp+08]
[00000d02](01)  50                      push eax       ; push D
[00000d03](03)  8b4d08                  mov ecx,[ebp+08]
[00000d06](01)  51                      push ecx       ; push D
[00000d07](05)  e800feffff              call 00000b0c  ; call H
[00000d0c](03)  83c408                  add esp,+08
[00000d0f](02)  85c0                    test eax,eax
[00000d11](02)  7404                    jz 00000d17
[00000d13](02)  33c0                    xor eax,eax
[00000d15](02)  eb05                    jmp 00000d1c
[00000d17](05)  b801000000              mov eax,00000001
[00000d1c](01)  5d                      pop ebp
[00000d1d](01)  c3                      ret
Size in bytes:(0034) [00000d1d]
>
In order for D simulated by H to have the same behavior as the
directly executed D(D) H must ignore the instruction at machine
address [00000d07]. *That is an incorrect simulation of D*
>
No, H can, and must, simulate the call instruction correctly.
>
>
*Ah so you finally admit that the directly executed D(D) that*
*cannot possibly reach this instruction *is not* the behavior*
*of D correctly simulated by H that reaches this instruction*
*and simulates H simulating H*
>
 No, I admit that THIS H didn't do it,
*This H does do it*
D is correctly simulated by H and H simulates itself simulating D
as the above line of code requires.
The directly executed D(D) can't possibly reach that line of code
thus proving that it has different behavior than D correctly
simulated by H.
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer

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