Re: DDD correctly emulated by H0 --- Why Lie?

On 6/23/2024 7:24 PM, Richard Damon wrote:

On 6/23/24 8:08 PM, olcott wrote:

On 6/23/2024 6:44 PM, Richard Damon wrote:

On 6/23/24 7:34 PM, olcott wrote:

On 6/23/2024 5:58 PM, Richard Damon wrote:

On 6/23/24 6:45 PM, olcott wrote:

>
You know what the freak I was talking from prior
discussions unless your brain is so damaged that
you can't remember anything from one post to the next.
>
In the case that you affirm that your brain <is>
this damaged then I humbly apologize.
>

>
>
No, you don't know what you are talking about.
>

So you insist on lying about this verified fact?
>
_DDD()
[00002172] 55               push ebp
[00002173] 8bec             mov ebp,esp
[00002175] 6872210000       push 00002172 ; push DDD
[0000217a] e853f4ffff       call 000015d2 ; call H0(DDD)
[0000217f] 83c404           add esp,+04
[00002182] 5d               pop ebp
[00002183] c3               ret
Size in bytes:(0018) [00002183]
>
According to the semantics of the x86 programming language
when DDD correctly emulated by H0 calls H0(DDD) this call
cannot possibly return.
>

>
I won't say it can't be true, but it hasn't been proven, largely because it seems you don't know how to do a formal logic proof.
>

>
Liar
>

 Then where is the proof?
 And were is the simulation that H0 did?
 Failure to show where you ACTUALLY PROVED it just shows you a liar.
 Remember the parts of a Formal Logic Proof:
 

You could disagree that 2 + 3 = 5 on this same Jackass basis.
2 + 3 = 5 ON THE FREAKING BASIS OF THE SEMANTICS OF ARITHMETIC.
According to the semantics of the x86 programming language
when DDD correctly emulated by H0 calls H0(DDD) this call
cannot possibly return.
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer