Re: a sed question

Liste des GroupesRevenir à cu shell 
Sujet : Re: a sed question
De : smirzo (at) *nospam* example.com (Salvador Mirzo)
Groupes : comp.unix.shell
Date : 21. Dec 2024, 13:17:20
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <87ed21xmb3.fsf@example.com>
References : 1 2
Janis Papanagnou <janis_papanagnou+ng@hotmail.com> writes:

On 18.12.2024 20:46, Salvador Mirzo wrote:
(*) Summary
 
I wrote a sed script that makes a line replacement after it finds the
right spot.  So far so good.  Then I added quit command after the
change, but the quit does not seem to take effect---violating my
expectation.  I'll appreciate any help on understanding what's going on.
>
First (before I forget it) change your string comparison '<' to the
numerical comparison operator '-lt' as in:   test $# -lt 2 && usage
Otherwise, if you get used to using the wrong operator, you may get
subtle errors in future if you continue that habit.

Changed.  Why is it the wrong operator?  It seems it's not the standard
one---checking just now on the POSIX.1 spec.  I think I just tried it
out and given it worked as expected, I didn't think of checking it.  I'm
new to the whole thing.

Also note that using $* may not work correctly (e.g. depending on
filenames [containing spaces] used). The safe form is a quoted  "$@"

I learned something here.

--8<-------------------------------------------------------->8---
$ cat script.sh
#!/bin/sh
echo dollar-star $*
./script dollar-star $*

echo quoted-dollar-star "$*"
./script "$*"

echo dollar-at $@
./script $@

echo quoted-dollar-at "$@"
./script "$@"

$ cat script.c
#include <stdio.h>

int main(int argc, char *argv[]) {
  printf("\nfull cmdline: ");
  for (int i = 0; i < argc; ++i) {
    printf("%s ", argv[i]);
  }
  printf("\nargs: %d\n", argc);
  for (int i = 0; i < argc; ++i) {
    printf("arg %d: %s\n", i, argv[i]);
  }
  return 0;
}
--8<-------------------------------------------------------->8---

$ ./script.sh 1 2 "th ree"
dollar-star 1 2 th ree

full cmdline: ./script dollar-star 1 2 th ree
args: 6
arg 0: ./script
arg 1: dollar-star
arg 2: 1
arg 3: 2
arg 4: th
arg 5: ree
quoted-dollar-star 1 2 th ree

full cmdline: ./script 1 2 th ree
args: 2
arg 0: ./script
arg 1: 1 2 th ree
dollar-at 1 2 th ree

full cmdline: ./script 1 2 th ree
args: 5
arg 0: ./script
arg 1: 1
arg 2: 2
arg 3: th
arg 4: ree
quoted-dollar-at 1 2 th ree

full cmdline: ./script 1 2 th ree
args: 4
arg 0: ./script
arg 1: 1
arg 2: 2
arg 3: th ree
$

(Then I was tempted to make a similar comment as Kenny. But...)

I'm studying and I often go back to the past to see what life was I
like.  I initially tried to solve the problem with /ed/, but did not
find a way to insert a string coming from the a shell script's cmdline.
Then I thought that /sed/ was there to make /ed/ more scriptable.

WRT your question I'd be interested to understand more about the
intention of your original question...

The intention is mostly in the paragraph above, but the way I study is
to put things in real-world practice as much as possible.  (When I
realize the solution is indeed too old to make sense, I replace it.
Otherwise I stick with it.)  I have a literate programming file that
contains a chunk that's the version of the program I'm writing.  So when
you ask the program its version, the information is included in the
executable, an idea which I like.  I get the version with a git command
such as

$ git log --oneline | head -1 | awk '{print $1}'
2566d31

So I wanted to include such string in the literate programming file.  At
first I wrote a solution in the programming language I'm using, but I
remember seeing many older software using sed for something like that,
so I decided to study sed a bit.  I read the sed part of Dale Dougherty
and Arnold Robbins's book "sed & awk", second edition, and I thought sed
was quite neat and sensible.  What I'm noticing now is that there are
too many different sed behavior out there to make it sensible to use.
UNIX systems as a whole are like that, so I'm used to reminding myself
of using the common subset of everything.  Perhaps the common subset of
sed is too small.  If I have to use it just for search and replace, then
perhaps it's not really worth it.

I mean if you don't trust your 'sed' command just pipe it though
'less'; there's no need to change the 'sed' program just for that.
>
Personally I'd try whether it works (by adding "something" before
and also after the desired place in your sample.txt to be sure the
other occurrences were not changed), and then just call
>
  sed -e '/<<Release>>=/,+1s/something/sth else/'  sample.txt
>
to see it working.

Thanks for the excellent instruction!

Date Sujet#  Auteur
18 Dec20:46 * a sed question48Salvador Mirzo
18 Dec21:12 +- Re: a sed question1John-Paul Stewart
19 Dec02:14 +* Re: a sed question16Ralf Damaschke
19 Dec13:05 i`* Re: a sed question15Salvador Mirzo
20 Dec01:55 i `* Re: a sed question14Ralf Damaschke
20 Dec13:44 i  `* Re: a sed question13Kenny McCormack
21 Dec01:17 i   `* Re: a sed question12Ralf Damaschke
21 Dec04:09 i    `* Re: a sed question11Kaz Kylheku
21 Dec04:36 i     +* sed... (Was: a sed question)8Kenny McCormack
21 Dec04:57 i     i`* Re: sed... (Was: a sed question)7Kaz Kylheku
21 Dec15:38 i     i +* Re: sed... (Was: a sed question)4Janis Papanagnou
21 Dec17:29 i     i i`* Re: sed... (Was: a sed question)3Janis Papanagnou
21 Dec23:23 i     i i `* Re: sed...2Keith Thompson
22 Dec00:33 i     i i  `- Re: sed...1Janis Papanagnou
21 Dec22:46 i     i `* Re: sed... (Was: a sed question)2Lars Poulsen
22 Dec22:22 i     i  `- Re: sed... (Was: a sed question)1Kaz Kylheku
21 Dec15:35 i     +- Re: a sed question1Janis Papanagnou
22 Dec01:43 i     `- Re: a sed question1Ralf Damaschke
20 Dec15:55 +* Re: a sed question18Janis Papanagnou
20 Dec16:11 i+* Checking for right # of args in a shell script (Was: a sed question)3Kenny McCormack
20 Dec16:49 ii`* Re: Checking for right # of args in a shell script (Was: a sed question)2Janis Papanagnou
20 Dec18:43 ii `- Re: Checking for right # of args in a shell script (Was: a sed question)1Kenny McCormack
21 Dec13:17 i+* Re: a sed question13Salvador Mirzo
21 Dec16:19 ii+* Re: a sed question7Janis Papanagnou
21 Dec22:41 iii`* Re: a sed question6Keith Thompson
22 Dec00:50 iii `* Re: a sed question5Janis Papanagnou
22 Dec01:26 iii  +* Re: a sed question2Keith Thompson
22 Dec01:41 iii  i`- Re: a sed question1Janis Papanagnou
22 Dec01:31 iii  `* Re: a sed question2Lawrence D'Oliveiro
22 Dec02:06 iii   `- Re: a sed question1Janis Papanagnou
21 Dec16:34 ii+* Re: a sed question4Andy Walker
21 Dec17:14 iii+- Re: a sed question1Janis Papanagnou
21 Dec19:21 iii`* Re: a sed question2Salvador Mirzo
21 Dec20:48 iii `- Re: a sed question1Janis Papanagnou
21 Dec19:20 ii`- Re: a sed question1Helmut Waitzmann
22 Dec19:23 i`- Re: a sed question1Janis Papanagnou
21 Dec15:13 `* Re: a sed question12Ed Morton
21 Dec22:09  `* Re: a sed question11Lawrence D'Oliveiro
22 Dec01:02   +* Re: a sed question8Janis Papanagnou
22 Dec01:28   i`* Re: a sed question7Lawrence D'Oliveiro
22 Dec01:36   i +* Re: a sed question5Keith Thompson
22 Dec02:52   i i`* Re: a sed question4Lawrence D'Oliveiro
22 Dec06:09   i i `* Re: a sed question3Keith Thompson
22 Dec06:56   i i  `* Re: a sed question2Lawrence D'Oliveiro
22 Dec07:55   i i   `- Re: a sed question1Keith Thompson
22 Dec02:22   i `- Re: a sed question1Janis Papanagnou
22 Dec02:09   +- Re: a sed question1Kenny McCormack
22 Dec21:03   `- Re: a sed question1Kaz Kylheku

Haut de la page

Les messages affichés proviennent d'usenet.

NewsPortal