Checking for right # of args in a shell script (Was: a sed question)

In article <vk40gi$3g9sm$1@dont-email.me>,
Janis Papanagnou  <janis_papanagnou+ng@hotmail.com> wrote:

On 18.12.2024 20:46, Salvador Mirzo wrote:

(*) Summary
 
I wrote a sed script that makes a line replacement after it finds the
right spot.  So far so good.  Then I added quit command after the
change, but the quit does not seem to take effect---violating my
expectation.  I'll appreciate any help on understanding what's going on.

>
First (before I forget it) change your string comparison '<' to the
numerical comparison operator '-lt' as in:   test $# -lt 2 && usage
Otherwise, if you get used to using the wrong operator, you may get
subtle errors in future if you continue that habit.

Agreed, in general, but in practice, the need rarely arises.

The idiomatic way to do this is just:

    [ $# = 2 ] || usage()

Also, when I need to do more complex arg verification, I use bash's [[ ]]
mechanism (Yes, I know OP is using /bin/sh, but there is no reason nowadays
not to use bash).  Say I want there to be 2 or 3 args (no other # is
acceptable and the 2nd arg must be numeric.  Like this:

    [[ $#,$2 =~ ^[23],[0-9]+$ ]] || { echo "Arg error!"; exit; }

--
On the subject of racism being depicted in the media, the far right and the far left have
met up in agreement (sort of like how plus infinity meets up with minus infinity).
The far left doesn't want it, because they are afraid it will make people racist.
The far right doesn't want it, because they are afraid it will make people feel bad about being racist.