Re: [SR and synchronization] Cognitive Dissonances and Mental Blockage

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Sujet : Re: [SR and synchronization] Cognitive Dissonances and Mental Blockage
De : python (at) *nospam* invalid.org (Python)
Groupes : sci.physics.relativity
Date : 27. Aug 2024, 10:58:35
Autres entêtes
Organisation : CCCP
Message-ID : <vak80b$2u8l5$1@dont-email.me>
References : 1 2 3 4
User-Agent : Mozilla Thunderbird
Le 27/08/2024 à 07:32, Thomas Heger a écrit :
Am Montag000026, 26.08.2024 um 09:06 schrieb Mikko:
...
Relativity requires mutally symmetric methods. So if you synchronize clock B with clock A, this must come to the same result, as if you would synchronize clock A with clock B.
>
No, it does not mutually symmetric methods. Such methods make the
presentation of the theory easier but do not affect the theory.
Einstein chose a symmetric method because otherwise his text would
be harder to read and understand.
 The very word 'relativity' requires mutually symmetric perspectives.
 This goes like this:
 you stand there, I stand here and I see you.
 Now the opposite should also be possible, but from your perspective.
 This means: you see me, while you would call yourself 'I', your own location 'here' and mine 'there'.
 This would give:
 you stand there, I stand here and I see you (but said by you and from your point of view).
  Since both perspectives are of equal rights, we need to accept both views as valid, hence need mutually symmetric perspectives.
 
But this requirement was not fullfilled in Einstein's scheme, because Einstein didn't take delay into consideration.
>
So you say but cannot prove.
 Negative statements are difficult to prove.
 But I can ask you, to prove the opposite and prove, that you failed.
 So: where exactly did Einstein take delay into consideration in his 1905 paper??
In paragraph I.1 in Einstein's 1905 article you can read :
(*)   2AB/(t'_A - t_A) = c
(**)  t_B - t_A = t'_A - t_B
In a setup with two mutually  at rest clocks at position A and B in
a given system of reference. --> and <-- represents a light signal
emission/reception, all time values are recorded by both clocks at
time or receptions/re-emission:
Step 1:
A-->               B
t_A
Step 2:
A               -->B
                  t_B
A               <--B
Step 3:
A<--               B
t'_A
So if you read the only equations in paragraph I.1,
assuming clocks are synchronized (which is the point of
this paragraph: state what it MEANS to be synchronized):
(*)   2AB/(t'_A - t_A) = c
(**)  t_B - t_A = t'_A - t_B
t_B - t_A is a *delay* (between emission at A and reception at B)
t_'A - t_B is a *delay* (between emission at B and reception at A)
t'A - t_A is a *delay* (round trip time *delay* for a light signal
going from A to B bounced back to A)
 From (*) you can get : t'_A - t_A = 2AB/c so another way to
describe the same *delay* : twice the distance AB divided by c.
Clearly such a *delay* is present in paragraph I.1. THREE times
as a term in an equation and ONCE as a term you can obtain by
ONE step of basic algebra.
It is difficult to believe you've "overlooked" this and continue
to do so for YEARS.
You are acting like a fool in a shop who'd rob some merchandise
which had a price marked on it on the ground that it is nowhere
written explicitly that you have to *pay* for it.
At first it could have been a symptom of your complete inability
to understand a single sentence of the article (i.e. sheer stupidity),
since you've published your idiotic comments and got some clues from
numerous people here it is definitely a symptom of your dishonesty
Thomas.

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