Sujet : Re: (1 Combination 2) = 0 -- Better explanation?
De : jbb (at) *nospam* notatt.com (Jeff Barnett)
Groupes : comp.lang.python sci.math sci.langDate : 15. Jul 2024, 04:44:30
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Message-ID : <v725uv$hnvc$1@dont-email.me>
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On 7/14/2024 2:57 PM, HenHanna wrote:
Python says: (1 Combination 2) = 0
Ok... It's Impossible (to do).
------- is there a Better explanation?
(5 Combination 0) = 1 <---- This is explained by Comb(5,0)=Comb(5,5)
in general: Comb(N,r)=Comb(N,N-r)
_______________________________________
from math import comb
for i in range(6): print( comb(5,i) )
print( comb(1,2) )
Let combination of n things taken m at a time be represented by [n,m].
Then [n,m] = [n,n-m] as you correctly note above. Further, we have the
computational formula [n,m] = n!/(m!(n-m)!) where x! is simply x
factorial. So [1,2] = 1!/(2!((-1)!)), or 1/2 divided by (-1)!. However
factorial of a negative integer is, by convention, an infinite value so
[1.2] = 0.
-- Jeff Barnett