Sujet : Re: (1 Combination 2) = 0 -- Better explanation?
De : HenHanna (at) *nospam* devnull.tb (HenHanna)
Groupes : comp.lang.python sci.math sci.langDate : 15. Jul 2024, 19:49:39
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v73r04$ql49$2@dont-email.me>
References : 1 2
User-Agent : Mozilla Thunderbird
On 7/14/2024 8:44 PM, Jeff Barnett wrote:
On 7/14/2024 2:57 PM, HenHanna wrote:
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Python says: (1 Combination 2) = 0
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Ok... It's Impossible (to do).
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------- is there a Better explanation?
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(5 Combination 0) = 1 <---- This is explained by Comb(5,0)=Comb(5,5)
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in general: Comb(N,r)=Comb(N,N-r)
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_______________________________________
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from math import comb
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for i in range(6): print( comb(5,i) )
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print( comb(1,2) )
Let combination of n things taken m at a time be represented by [n,m]. Then [n,m] = [n,n-m] as you correctly note above. Further, we have the computational formula [n,m] = n!/(m!(n-m)!) where x! is simply x factorial. So [1,2] = 1!/(2!((-1)!)), or 1/2 divided by (-1)!. However factorial of a negative integer is, by convention, an infinite value so [1.2] = 0.
THank you...
Bard.Google.com says that
Comb(1,2) is not defined
factorial(-1) is not defined
factorial(-2) is not defined
GammaFunction(-1) is not defined
GammaFunction(-2) is not defined