Sujet : Re: Maximize Cistern Volume -- (cut out 4 squares (at Corners) and discard them)
De : richard (at) *nospam* cogsci.ed.ac.uk (Richard Tobin)
Groupes : rec.puzzles sci.lang sci.mathDate : 03. May 2025, 20:01:15
Autres entêtes
Organisation : Language Technology Group, University of Edinburgh
Message-ID : <vv5p5r$2lbu9$1@artemis.inf.ed.ac.uk>
References : 1
User-Agent : trn 4.0-test76 (Apr 2, 2001)
In article <016b2820b7160c571e97a7f320260176@
www.novabbs.com>,
HenHanna <
HenHanna@dev.null> wrote:
I let the derivative be 0 and solve it , and i get x = 1/2, 1/6
>
at x=0 the slope is 1
whereas at x=1/2, the slope is Zero!!!
>
_______________
>
at x=1/2, the slope is Zero!!!
>
It's not obvious why, Can someone explain this?
When x is 1/2 the side of the cistern has shrunk to zero, the height
is 1/2, and the volume is zero. Physically, x can't exceed 1/2, but
the formula just produces a negative length for the side of the
cistern (along with a height greater then 1/2). That gives a positive
volume (the negative length is squared), so x=1/2 is a minimum for the
volume.
-- Richard