Liste des Groupes | Revenir à s logic |
On 2025-07-05 13:15:11 +0000, WM said:It is so by definition. See e.g. W. Mückenheim: "Mathematik für die ersten Semester", 4th ed., De Gruyter, Berlin (2015).
On 05.07.2025 10:37, Mikko wrote:So you say but cannot prove.On 2025-07-04 12:32:55 +0000, WM said:>>I only said: The definition of bijection requires completeness.>
>
You: No, it doesn't.
I also said what is worng in your claim: bijection only requires that
there is one and only one element of co-domain for each element of
domain, regardless of completeness.
Bijection requires completeness of domain and codomain.
Les messages affichés proviennent d'usenet.