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Op 12.jul.2025 om 17:21 schreef olcott:void DDD()On 7/12/2025 3:17 AM, Fred. Zwarts wrote:Irrelevant, because that is not what HHH does.Op 11.jul.2025 om 23:05 schreef olcott:>On 7/11/2025 3:52 AM, Fred. Zwarts wrote:>Op 10.jul.2025 om 16:35 schreef olcott:>On 7/10/2025 5:54 AM, Fred. Zwarts wrote:>Op 09.jul.2025 om 15:02 schreef olcott:>>All Turing machine deciders only compute the mapping>
from their actual inputs. This entails that they never
compute any mapping from non-inputs.
At least one thing you understand.
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*From the bottom of page 319 has been adapted to this*
https://www.liarparadox.org/Peter_Linz_HP_317-320.pdf
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*The Linz proof does not understand this*
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When Ĥ is applied to ⟨Ĥ⟩
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.∞
*if Ĥ applied to ⟨Ĥ⟩ halts, and*
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.embedded_H ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.qn
*if Ĥ applied to ⟨Ĥ⟩ does not halt*
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>*It is common knowledge in the theory of computation*>>The evidence is that the input includes the code to abort and halt,>
abort and stop running
*IS NOT THE SAME THING AS*
abort and halt
Another claim without evidence.
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>
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Another claim without evidence.
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*Your lack of knowledge of computer science is not a rebuttal*
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Look at the definition of a Turing Machine (e.g., the one here). The machine has states. Each state can be final or non-final. If the machine's state is non-final, in the next step the machine "does" something, namely, it can write something on the tape, move its head, and/or change its state to a different state. This is how the machine makes a progress.
So, aborting the simulation when the machine has not yet reached its final state, is a violation of the Turing Machine.
>
void DDD()
{
HHH(DDD);
return;
}
>
So you don't understand that DDD simulated by
pure simulator HHH keeps repeating its first
line forever?
You do not understand that when HHH aborts and returns to DDD then DDD will halt.The next step of my proof would have addressed this.
Probably you are dreaming again of the HHH that does not abort. Dremas are no substitute for facts.--
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