Re: Flat out dishonest or totally ignorant? Yes to both for Peter Olcott

On 7/3/24 10:19 AM, olcott wrote:

On 7/3/2024 9:11 AM, joes wrote:

Am Tue, 02 Jul 2024 22:55:12 -0500 schrieb olcott:

On 7/2/2024 10:50 PM, joes wrote:

Am Tue, 02 Jul 2024 14:46:38 -0500 schrieb olcott:

On 7/2/2024 2:17 PM, Fred. Zwarts wrote:

Op 02.jul.2024 om 21:00 schreef olcott:

On 7/2/2024 1:42 PM, Fred. Zwarts wrote:

Op 02.jul.2024 om 14:22 schreef olcott:

On 7/2/2024 3:22 AM, Fred. Zwarts wrote:

Op 02.jul.2024 om 03:25 schreef olcott:

>

HHH repeats the process twice and aborts too soon.

>
DDD is correctly emulated by any HHH that can exist which calls this
emulated HHH(DDD) to repeat the process until aborted (which may be
never).

Whatever HHH does, it does not run forever but aborts.
>

HHH halts on input DDD.
DDD correctly simulated by HHH cannot possibly halt.

WTF? It only calls HHH, which you just said halts.
>

 An aborted simulation does not count as halting.

And doesn't show non-halting either.

Reaching it own machine address 00002183 counts as halting.
DDD correctly simulated by HHH cannot possibly do that.

But HHH doesn't DO a "Correct Simulation" that can show that, it only does a PARTIAL simulation.
The COMPLETE simulation of THAT input (still calling HHH) shows that DDD does halt.
And thus, you are proven to be a liar and an idiot at the same time as this HAS been explained to you many times, but you seem unable and unwilling to learn.

 _DDD()
[00002172] 55               push ebp      ; housekeeping
[00002173] 8bec             mov ebp,esp   ; housekeeping
[00002175] 6872210000       push 00002172 ; push DDD
[0000217a] e853f4ffff       call 000015d2 ; call HHH(DDD)
[0000217f] 83c404           add esp,+04
[00002182] 5d               pop ebp
[00002183] c3               ret
Size in bytes:(0018) [00002183]