Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary)

On 11/28/24 7:20 AM, WM wrote:

On 27.11.2024 22:20, Richard Damon wrote:

On 11/27/24 3:09 PM, WM wrote:

 

It is completed! Every number 10n starts wit a black hat.

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Right, and it gives that hat to n, so every number gets one.
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And, 10n will get back a hat from 100n, so it still have one at the end.
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It seems so, but that is impossible. Up to every 10n, the interval 1, 2, 3, ... 10n has a covering of 1/10 only. The limit of this sequence is 1/10 too. And since this is true for all natural numbers, where should additional hats come from?
 Regards, WM
 

No, it is possilbe, but beyond your understanding, because you refuse to actually work with the infinite set, and think a finite set is an adiquite model for the inifinite.
Sorry, you are just proving your incompetence.