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On 3/8/2024 10:09 AM, immibis wrote:Peter Linz Ĥ ⟨Ĥ⟩ is a Turing machine. The exact same proof does not work for Olcott machines because they are different. A different proof proves that Olcott machines cannot compute the halting problem. I have already told you this proof (but not in great detail).On 8/03/24 07:30, olcott wrote:Let's first determine that Olcott machines refuteĤ.H ⟨Ĥ⟩ ⟨Ĥ⟩ <Ĥ> immediately detects that is about to simulate a>
copy of itself with a copy of its own input thus immediately
detects recursive simulation just like H(D,D).
>
H ⟨Ĥ⟩ ⟨Ĥ⟩ <H> immediately detects that is NOT about to simulate a
copy of itself with a copy of its own input thus immediately
rejects recursive simulation just like H1(D,D).
And what about Ĥ.H ⟨Ĥ⟩ ⟨Ĥ⟩ <H> ?
>
the uncomputability of the Peter Linz ⟨Ĥ⟩ ⟨Ĥ⟩.
Because my cancer came back in less than 24 months thatThen why do you keep doing it?
means I don't have time for endless divergence.
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