Sujet : Re: ZFC solution to incorrect questions: reject them
De : polcott2 (at) *nospam* gmail.com (olcott)
Groupes : comp.theory sci.logicDate : 14. Mar 2024, 22:59:05
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <usvoep$1rdem$2@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33
User-Agent : Mozilla Thunderbird
On 3/14/2024 3:54 PM, Richard Damon wrote:
On 3/14/24 1:26 PM, olcott wrote:
On 3/14/2024 3:20 PM, Richard Damon wrote:
On 3/14/24 12:32 PM, olcott wrote:
On 3/14/2024 12:33 PM, Richard Damon wrote:
On 3/13/24 4:04 PM, olcott wrote:
On 3/13/2024 5:43 PM, Richard Damon wrote:
On 3/13/24 2:54 PM, olcott wrote:
On 3/13/2024 4:39 PM, Richard Damon wrote:
On 3/13/24 1:52 PM, olcott wrote:
On 3/13/2024 12:52 PM, Richard Damon wrote:
On 3/13/24 10:08 AM, olcott wrote:
On 3/13/2024 11:44 AM, immibis wrote:
On 13/03/24 04:55, olcott wrote:
On 3/12/2024 10:49 PM, Richard Damon wrote:
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Not quite. It always gets the wrong answer, but only one of them for each quesiton.
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They all gets the wrong answer on a whole class of questions
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Wrong. You said. yourself. that H1 gets the right answer for D.
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Since it is a logical impossibility to determine the truth
value of a self-contradictory expression the requirement
for H to do this is bogus.
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Shows you are just a LIAR, as there IS a truth value to the expression that is the requirment for ANY SPECIFIC H.
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*Lying about me being a liar may possibly cost your soul*
*Lying about me being a liar may possibly cost your soul*
*Lying about me being a liar may possibly cost your soul*
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There is no mapping from H(D,D) to Halts(D,D) that exists.
This proves that H(D,D) is being asked an incorrect question.
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Why, because it is NOT a LIE.
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You don't even know the definiton of an incorrect question.
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I invented it so I get to stipulate its meaning.
https://groups.google.com/g/sci.lang/c/AO5Vlupeelo/m/nxJy7N2vULwJ
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Nope, common technical term.
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Cite a source.
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The fact that there DOES exist a mapping Halt(M,d) that maps all Turing Machines and there input to a result of Halting / Non-Halting for EVERY member of that input set, means tha Halts is a valid mapping to ask a decider to try to decider.
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That part is true.
Likewise when you ask a man that has never been married:
Have you stopped beating tour wife?
There are some men that have stopped beating their wife.
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Right, because that question include a presumption of something not actually present.
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Although there is a mapping from some men to YES/NO
there is no mapping from never unmarried men to YES/NO
thus the question is incorrect for all unmarried men.
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Although there is a mapping from some TM/input pairs to YES/NO
there is no mapping from H/D to YES/NO
thus the question is incorrect for H/D
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Except that the mapping requested is about the INPUTS to H, not H itsef.
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In order to see that it is an incorrect question we must examine
the question in detail. Making sure to always ignore this key detail
<is> cheating.
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Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.Hq0 ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.Hqy ∞ // Ĥ applied to ⟨Ĥ⟩ halts
Ĥ.q0 ⟨Ĥ⟩ ⊢* Ĥ.Hq0 ⟨Ĥ⟩ ⟨Ĥ⟩ ⊢* Ĥ.Hqn // Ĥ applied to ⟨Ĥ⟩ does not halt
∀Ĥ.H (Ĥ.H ⟨Ĥ⟩ ⟨Ĥ⟩ != Halts(⟨Ĥ⟩, ⟨Ĥ⟩))
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Which isn;t the question at all, so you are just shown to be a stupid liar.
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The QUESTION is:
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Does the machine and input described by this input, Halt when run?
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The question posed to Ĥ.H has no correct answer, thus not the
same question at all.
But it DOES.
Then tell me which element of:
∀Ĥ.H (Ĥ.H ⟨Ĥ⟩ ⟨Ĥ⟩ != Halts(⟨Ĥ⟩, ⟨Ĥ⟩)) is correct and make sure that
you explain why this element is correct and don't try to switch
to any other element outside of the above specified set.
-- Copyright 2024 Olcott "Talent hits a target no one else can hit; Geniushits a target no one else can see." Arthur Schopenhauer
ZFC solution to incorrect questions: reject them
Re: ZFC solution to incorrect questions: reject them --Gödel--