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On 16/03/24 20:55, olcott wrote:Do you understand that an algorithm can be encoded in anĤ.H is not gagged unable to answer.I've noticed that every time you talk about "every" or "infinite sets" it doesn't make sense.
Every element of the infinite set of Ĥ.H ⟨Ĥ⟩ ⟨Ĥ⟩ only gets
the wrong answer because its answer is contradicted.
"The infinite set of Ĥ.H ⟨Ĥ⟩ ⟨Ĥ⟩" doesn't make a lot of sense the way it's written.For every possible way that H can be encoded Ĥ.H ⟨Ĥ⟩ ⟨Ĥ⟩
It's true that for every program P (I will not call it H because that will confuse you), P(GetCounterexampleProgram(P), GetCounterexampleProgram(P)) != Halts(GetCounterexampleProgram(P), GetCounterexampleProgram(P))
This does not mean that Halts(GetCounterexampleProgram(P), GetCounterexampleProgram(P)) has no answer.
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