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On 3/23/2024 9:43 AM, Fred. Zwarts wrote:Even a beginner in C will see that if the simulated D, using the H that is programmed to abort and return false, will continue with line 04 then line 06 and halt (unless aborted).Op 23.mrt.2024 om 14:58 schreef olcott:You still do not understand that functions called in infiniteOn 3/23/2024 4:38 AM, Fred. Zwarts wrote:>Op 22.mrt.2024 om 19:41 schreef olcott:>01 int D(ptr x) // ptr is pointer to int function>
02 {
03 int Halt_Status = H(x, x);
04 if (Halt_Status)
05 HERE: goto HERE;
06 return Halt_Status;
07 }
08
09 void main()
10 {
11 H(D,D);
12 }
>
H is a simulating abort decider that supposed to
correctly determine whether or not it needs to abort
the simulation of any pathological inputs that are
attempting to thwart this abort decision.
>
H must abort every simulated input that would not
otherwise halt to prevent its own non-termination.
>
It is a self-evident verified fact that every H(D,D)
that decides to abort its simulated D(D) is correct
in doing so because this does prevent its own
non-termination.
>
It is self-evident that when H is programmed to abort and return false, then [the simulated] D will
immediately stop running never having reached its last instruction to halt.
As can be seen above, if H returns false in line 03, then D will go to line 04 and line 06 and halt (unless aborted).
>
recursion never return to their caller, thus must have grossly
exaggerated your programming skill.
When the simulated D calls its simulator this call cannot possiblyIt is exactly the relation with the simulator that aborts, which makes that also the simulated H is programmed to abort and return false.
return to its caller. The relationship between the simulated D(D)
and its simulator makes a call D(D) to its own simulator isomorphic
to infinite recursion.
That the directly executed D(D) is an entirely different instanceI am not talking about a directly executed D, but a simulated D!
that does not have this same pathological relationship is summed
up in your own reply.
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