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x ∉ True if and only if pBut, your final sentence no longer DEFINES what p is, it just references an undefined term, whch is an error.
where the symbol 'p' represents the whole sentence x
https://liarparadox.org/Tarski_275_276.pdf
First we convert the clumsy indirect approximation of
self-reference by getting rid of the extraneous x we
also swap the LHS with the RHS.
p if and only if p ∉ True
ψ ↔ ϕ⟨ψ⟩ … The sentence ψ is of course not self-referential
in a strict sense, but mathematically it behaves like one.”
https://plato.stanford.edu/entries/self-reference/
Thus Stanford acknowledges that it is formalizing self-reference
incorrectly in its article about self-reference. This seems to
be the standard convention for all papers that formalize the Liar
Paradox.
Here is actual self-reference
x := y means x is defined to be another name for y
https://en.wikipedia.org/wiki/List_of_logic_symbols
Next we turn this into actual self-reference
p := p ∉ True
Next we limit the scope to one formal system with a predicate
p := ~True(L, p)
Next we change the name to the more recognizable name
LP := ~True(L, LP)
<Tarski Undefinability>
We shall show that the sentence x is actually undecidable
and at the same time true ...(page 275)
the proof of
the sentence x given in the meta-theory can automatically be
carried over into the theory itself: the sentence x which is
undecidable in the original theory becomes a decidable sentence
in the enriched theory. (page 276)
https://liarparadox.org/Tarski_275_276.pdf
</Tarski Undefinability>
*When we stick with theory L we get the same results*
*thus no need for any meta-theory*
True(L, LP) is false
True(L, ~LP) is false
Truthbearer(L,x) ≡ (True(L,x) ∨ True(L,~x))
So what Tarski says is undecidable in his theory is actually
not a truth-bearer in his theory.
What Tarski said is provable in his meta-theory making it true
in his theory is ~True(L, LP) is true in his theory because
LP is not a truth-bearer in L.
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