Re: D correctly simulated by H cannot possibly reach its own line 06 and halt

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Sujet : Re: D correctly simulated by H cannot possibly reach its own line 06 and halt
De : mikko.levanto (at) *nospam* iki.fi (Mikko)
Groupes : comp.theory
Date : 01. Jun 2024, 09:56:24
Autres entêtes
Organisation : -
Message-ID : <v3ek78$2mbgo$1@dont-email.me>
References : 1 2 3 4
User-Agent : Unison/2.2
On 2024-05-31 14:25:40 +0000, olcott said:

On 5/31/2024 2:50 AM, Fred. Zwarts wrote:
Op 31.mei.2024 om 00:01 schreef olcott:
On 5/30/2024 4:54 PM, joes wrote:
Am Thu, 30 May 2024 09:55:24 -0500 schrieb olcott:
 
typedef int (*ptr)();  // ptr is pointer to int function in C
00       int H(ptr p, ptr i);
01       int D(ptr p)
02       {
03         int Halt_Status = H(p, p);
04         if (Halt_Status)
05           HERE: goto HERE;
06         return Halt_Status;
07       }
08
09       int main()
10       {
11         H(D,D);
12         return 0;
13       }
 The left hand-side are line numbers of correct C code.
This code does compile and does conform to c17.
 Everyone with sufficient knowledge of C can easily determine that D
correctly emulated by any *pure function* H (using an x86 emulator)
cannot possibly reach its own simulated final state at line 06 and halt.
Yeah, of course not, if H doesn’t halt.
 
 To actually understand my words (as in an actual honest dialogue)
you must pay careful attention to every single word. Maybe you
had no idea that *pure functions* must always halt.
 Or maybe you did not know that every computation that never reaches
its own final state *DOES NOT HALT* even if it stops running because
it is no longer simulated.
 Since the claim is that H is also a computation, it holds for H, as well. That means that H *DOES NOT HALT* even if it stops running because it is no longer simulated.
 
 *pure function H definitely halts you are confused*
A pure function does not halt (in C that means that a pure function
does not call exit). A pure function returns.
--
Mikko

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