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On 6/14/24 11:07 PM, olcott wrote:That is is over-your-head does not even make it untrue.On 6/13/2024 8:24 PM, Richard Damon wrote:You keep on stating that LIE.
> On 6/13/24 11:32 AM, olcott wrote:
>>
>> It is contingent upon you to show the exact steps of how H computes
>> the mapping from the x86 machine language finite string input to
>> H(D,D) using the finite string transformation rules specified by
>> the semantics of the x86 programming language that reaches the
>> behavior of the directly executed D(D)
>>
>
> Why? I don't claim it can.
>
_D()
[00000cfc](01) 55 push ebp
[00000cfd](02) 8bec mov ebp,esp
[00000cff](03) 8b4508 mov eax,[ebp+08]
[00000d02](01) 50 push eax ; push D
[00000d03](03) 8b4d08 mov ecx,[ebp+08]
[00000d06](01) 51 push ecx ; push D
[00000d07](05) e800feffff call 00000b0c ; call H
[00000d0c](03) 83c408 add esp,+08
[00000d0f](02) 85c0 test eax,eax
[00000d11](02) 7404 jz 00000d17
[00000d13](02) 33c0 xor eax,eax
[00000d15](02) eb05 jmp 00000d1c
[00000d17](05) b801000000 mov eax,00000001
[00000d1c](01) 5d pop ebp
[00000d1d](01) c3 ret
Size in bytes:(0034) [00000d1d]
>
If there is no mapping from the input to H(D,D) to the behavior
of D(D) then H is not even being asked about the behavior of D(D).
H has no obligation to answer questions *THAT IT IS NOT BEING ASKED*
>
H, being a Halting Decider (or are you lying about that) has exactly one question it *IS* being asked about every input it s given, that that is "Will the execution of the program represented by your input Halt when run?"Yes you are very good at memorizing textbooks now prove that the
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