Re: Simulating termination analyzers by dummies --- What does halting mean?

Liste des GroupesRevenir à s logic 
Sujet : Re: Simulating termination analyzers by dummies --- What does halting mean?
De : F.Zwarts (at) *nospam* HetNet.nl (Fred. Zwarts)
Groupes : comp.theory sci.logic
Date : 19. Jun 2024, 16:11:14
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v4uou1$1vtc8$3@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19
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Op 19.jun.2024 om 15:11 schreef olcott:
On 6/19/2024 3:18 AM, Fred. Zwarts wrote:
Op 18.jun.2024 om 19:25 schreef olcott:
On 6/18/2024 12:06 PM, joes wrote:
>
void DDD()
{
   H0(DDD);
}
>
DDD correctly simulated by any H0 cannot possibly halt.
>
DDD halts iff H0 halts.
>
Halting is a technical term-of-the-art that corresponds
to terminates normally. Because Turing machines are
abstract mathematical objects there has been no notion
of abnormal termination for a Turing machine.
>
We can derive a notion of abnormal termination for Turing
machines from the standard terms-of-the-art.
>
Some TM's loop and thus never stop running, this is classical
non-halting behavior. UTM's simulate Turing machine descriptions.
This is the same thing as an interpreter interpreting the
source-code of a program.
>
A UTM can be adapted so that it only simulates a fixed number
of iterations of an input that loops. When this UTM stops
simulating this Turing machine description we cannot correctly
say that this looping input halted.
>
>
If the code specifies 5 iterations and the simulator simulates only 3 iterations, it is incorrect to conclude that the repetition show non-halting behaviour.
 It is correct do say that the simulated input did not terminate
normally, thus defining the notion of abnormal termination
within Turing machines.
 
Similarly, when your H, H0, or other H simulates itself, its simulation aborts one cycle too early and therefore the non-halting conclusion is incorrect.
 I was confused bout this for three days four years ago and then I
got over it. No simulating termination analyzer can wait for an
inner instance of itself to abort the simulation or it waits forever.
 Whenever the outer directly executed simulating termination analyzer
waits for any fixed number of repeating states it remains permanently
ahead of the next inner instance by exactly one repeating state. If
this is going to be permanently over your head then we need to stop
talking.
No, I understand it perfectly, but it seems to be over your head. We agree that H needs to stop to prevent infinite recursion, but it is over your head to see that when it stops, it misses the part of itself where its simulation also stops, one repeating state further. So, the non-halting conclusion is wrong, because the abort is premature.
So, your reasoning must lead to the only possible conclusion that a simulator is unable to simulate itself properly, which causes false negatives if its return value must be interpreted as a non-halting behaviour. Instead, a return value of 'false' indicates an 'unable to simulate' state of the simulator, which is not equivalent to 'non-halting'.

Date Sujet#  Auteur
17 Jun 24 * Simulating termination analyzers for dummies115olcott
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