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Op 28.jun.2024 om 18:54 schreef olcott:void Infinite_Loop()On 6/28/2024 10:48 AM, Fred. Zwarts wrote:What you say is that two equals infinite.Op 28.jun.2024 om 17:32 schreef olcott:>>>
<MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
If simulating halt decider H correctly simulates its input D
until H correctly determines that its simulated D would never
stop running unless aborted then
>
H can abort its simulation of D and correctly report that D
specifies a non-halting sequence of configurations.
</MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>
On 10/14/2022 7:44 PM, Ben Bacarisse wrote:
> I don't think that is the shell game. PO really /has/ an H
> (it's trivial to do for this one case) that correctly determines
> that P(P) *would* never stop running *unless* aborted.
>
>
But there is no correct simulation, so Sipser's approval does not apply.
The semantics of the x86 programming language specifies that
N steps of DDD were correctly emulated until the infinite
recursion behavior pattern was correctly matched.
*We are not talking about infinite recursion. We are talking about a two cycle recursive simulation.*Sure there is. Why lie ?
>There is no infinite recursion pattern.
This has better color coding than the prior version.
https://liarparadox.org/HHH(DDD)_Full_Trace.pdf
>Let's agree about a two cycle recursive simulation, for which you have not shown any evidence that it can be done correctly.>
I have proven the verified fact that DDD is correctly emulated by
HHH and HHH correctly emulates itself emulating DDD until the outer
HHH sees that DDD meets the infinite recursion behavior pattern.
>
The simulated HHH runs one cycle behind the simulating HHH. The simulating HHH aborts the simulated HHH only one cycle before the simulated HHH would return.--
Aborting the simulation at this point makes it incorrect.
So, stop talking about infinite, because apparently do not understand what it means. Infinite is much more than two.
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