Re: 197 page execution trace of DDD correctly simulated by HHH

On 7/1/24 11:14 PM, olcott wrote:

On 7/1/2024 9:44 PM, Richard Damon wrote:

On 7/1/24 10:34 PM, olcott wrote:

On 7/1/2024 9:24 PM, Richard Damon wrote:

On 7/1/24 9:36 PM, olcott wrote:

On 7/1/2024 7:38 PM, Richard Damon wrote:

On 7/1/24 8:59 AM, olcott wrote:

On 7/1/2024 3:23 AM, Fred. Zwarts wrote:

Op 30.jun.2024 om 19:20 schreef olcott:

>
_DDD()
[00002172] 55               push ebp      ; housekeeping
[00002173] 8bec             mov ebp,esp   ; housekeeping
[00002175] 6872210000       push 00002172 ; push DDD
[0000217a] e853f4ffff       call 000015d2 ; call HHH(DDD)
[0000217f] 83c404           add esp,+04
[00002182] 5d               pop ebp
[00002183] c3               ret
Size in bytes:(0018) [00002183]
>

>
It cannot possibly return, because HHH aborts itself one cycle too early, showing that the emulation is incorrect. If that is over your head, try to learn how x86 instructions work.

>
_DDD()
[00002172] 55               push ebp      ; housekeeping
[00002173] 8bec             mov ebp,esp   ; housekeeping
[00002175] 6872210000       push 00002172 ; push DDD
[0000217a] e853f4ffff       call 000015d2 ; call HHH(DDD)
[0000217f] 83c404           add esp,+04
[00002182] 5d               pop ebp
[00002183] c3               ret
Size in bytes:(0018) [00002183]
>
DDD is correctly emulated by HHH which calls an
emulated HHH(DDD) to repeat the process until aborted.
>
>

>
CAN'T BE.
>
A "Correct Emulation" is one that produces the same result as the program at the input.
>

>
Which can only possibly occur be disregarding the semantics
of the x86 language. Liars would do that ignoramuses would do
that. Everyone with the equivalent of a BSCS would know that
what I said is true.
>
>

>
Why do you say that? That is EXACTLY the definition of Correct Emulation.

>
>
WELL INDOCTRINATED FALSE ASSUMPTIONS ARE NOT TRUTH.
WELL INDOCTRINATED FALSE ASSUMPTIONS ARE NOT TRUTH.
WELL INDOCTRINATED FALSE ASSUMPTIONS ARE NOT TRUTH.

>
And denying definitions is just lying.

 It may seem that way when you don't bother to pay
attention that this definition is contradicted
by verified facts.

WHAT "Verified facts".
THe fact that DDD will halt since your HHH(DDD) retuns?

 Indoctrination will cause this. The only cure is
correct reasoning by assuming that everything that
anyone ever told you about anything is possibly
false until conclusively proven otherwise.

Nope, but failure to follow the defined rules gets you kick out of the club.

 If everyone always did this then Nazi propaganda
could not possibly have any chance of success.

But THEY Lied, and to could be shown so,
Just like your statements.

 

>
void Infinite_Loop()
{
   HERE: goto HERE;
}
>
void Infinite_Recursion()
{
   Infinite_Recursion();
}
>
void DDD()
{
   HHH(DDD);
}
>
Every C programmer that knows what an x86 emulator is knows
that when HHH emulates the machine language of Infinite_Loop, Infinite_Recursion, and DDD that it must abort these emulations
so that itself can terminate normally.
>
SO THESE THREE INPUTS DO NOT FREAKING HALT
SO THESE THREE INPUTS DO NOT FREAKING HALT
SO THESE THREE INPUTS DO NOT FREAKING HALT
>

>
No, DDD does halt if HHH is a decider and HHH(DDD) returns.
>

 That is the same nutty bullshit as Gödel's 1931 incompleteness
theorem. If there are no truth preserving operations in PA to
either G or ~G then G has no truthmaker in PA making G not a
truth-bearer in PA.

But there ARE a set of truth preserving operations in PA to show G, it is just that it takes an infinite number of them, so they don't constitute a proof.
Something you don't seem to understand.

 We can say that this makes PA incomplete yet PA would be
incomplete in the same way that dogs do not climb trees
or lay eggs.
 

Nope, it is incomplete, because there is a truth established by an infinite number of steps, that can not be proven in a finite number of steps.
that you can't count, doesn't make it false, it makes you stupid.
And by repeating your stupid remarks after being corrected, a LIAR.