Re: DDD correctly emulated by HHH is correctly rejected as non-halting.

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Sujet : Re: DDD correctly emulated by HHH is correctly rejected as non-halting.
De : F.Zwarts (at) *nospam* HetNet.nl (Fred. Zwarts)
Groupes : comp.theory
Date : 12. Jul 2024, 15:32:28
Autres entêtes
Organisation : A noiseless patient Spider
Message-ID : <v6repr$32501$2@dont-email.me>
References : 1 2 3 4 5 6 7 8 9 10
User-Agent : Mozilla Thunderbird
Op 12.jul.2024 om 15:25 schreef olcott:
On 7/12/2024 3:15 AM, Mikko wrote:
On 2024-07-11 14:12:15 +0000, olcott said:
>
On 7/11/2024 1:28 AM, Mikko wrote:
On 2024-07-10 18:58:14 +0000, olcott said:
>
On 7/10/2024 1:55 PM, Alan Mackenzie wrote:
Fred. Zwarts <F.Zwarts@hetnet.nl> wrote:
Op 10.jul.2024 om 20:12 schreef Alan Mackenzie:
[ Followup-To: set ]
>
In comp.theory Fred. Zwarts <F.Zwarts@hetnet.nl> wrote:
>
[ .... ]
>
Proving that the simulation is incorrect. Because a correct simulation
would not abort a halting program halfway its simulation.
>
Just for clarity, a correct simulation wouldn't abort a non-halting
program either, would it?  Or have I misunderstood this correctness?
>
[ .... ]
>
>
A non-halting program cannot be simulated correctly in a finite time.
So, it depends whether we can call it a correct simulation, when it does
not abort. But, for some meaning of 'correct', indeed, a simulator
should not abort a non-halting program either.
>
OK, thanks!
>
>
In other words he is saying that when you do
1 step correctly you did 0 steps correctly.
>
That is possible as "correctly" has different meaning when talking
about steps from when talking about simulations.
>
>
*No that is always false*
When you did one anythings correctly then you did
more than zero anythings correctly.
>
If I only correcly do one thing that is not a part of my routine then
I don't do my routine correctly. If I do correctly every part of my routine
but do them in a wrong order I don't do my routine correctly.
>
 Fred was trying to get away with saying that when 1
step of DDD is correctly emulated by HHH that 0 steps
were emulated correctly.
 
Olcott has a problem with the English language.
I said that when a program needs 2 cycles of simulation, it is incorrect to abort after 1 cycle and decide it is non-halting.
His problem seems to be that he thinks that skipping x86 instructions in the simulation does not change the behaviour of a program.
There are more situations where he seems to have a problem with the English language. He thinks that everything greater than 2 equals infinity. When a program has more than two recursions, he thinks it is non-halting.
It is very difficult to discuss with someone with such a poor understanding of the English language, because he continuously twists the meaning of words, both his own words as well as the words of his opponents.

Date Sujet#  Auteur
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