Re: Every D(D) simulated by H presents non-halting behavior to H ###

On 5/15/2024 11:23 AM, joes wrote:

Am Wed, 15 May 2024 10:24:57 -0500 schrieb olcott:

On 5/15/2024 3:18 AM, Mikko wrote:

On 2024-05-14 14:35:42 +0000, olcott said:

 

That is not strictly conforming and hardly conforming at all.
>

What trivial syntactic error that has no effect what-so-ever on the
semantics do you believe remains?
A missing semi-colon?

What is H?
 

The example must be simple enough so that people unfamiliar with C will
not be overwhelmed by things such as: typedef int (*ptr)();
a return value of 0 from main() also might be a little confusing.
I am trying to fit the essence of my proof on a single page.

Then you can’t claim knowledge of C is required.
 

Knowledge of C is required to affirm or deny my statement.
Knowledge of programming is required to understand the gist
of what I am saying.
typedef int (*ptr)();  // ptr is pointer to int function
00 int H(ptr x, ptr x);
01 int D(ptr x)
02 {
03   int Halt_Status = H(x, x);
04   if (Halt_Status)
05     HERE: goto HERE;
06   return Halt_Status;
07 }
08
09 int main()
10 {
11   H(D,D);
12   return 0;
13 }
Any H/D pair matching the above template where
D(D) is simulated by the same H(D,D) that it calls
cannot possibly reach past its own line 03.
This is a simple software engineering verified fact.
--
Copyright 2024 Olcott "Talent hits a target no one else can hit; Genius
hits a target no one else can see." Arthur Schopenhauer