Re: At least 100 people kept denying the easily verified fact

On 2024-06-05 12:30:25 +0000, olcott said:

On 6/5/2024 6:31 AM, Richard Damon wrote:

On 6/4/24 11:21 PM, olcott wrote:

On 6/4/2024 10:15 PM, Richard Damon wrote:

On 6/4/24 10:55 PM, olcott wrote:

On 6/4/2024 9:45 PM, Richard Damon wrote:

On 6/4/24 10:28 PM, olcott wrote:

On 6/4/2024 9:22 PM, Richard Damon wrote:

On 6/4/24 9:54 PM, olcott wrote:

On 6/4/2024 8:48 PM, Richard Damon wrote:

On 6/4/24 5:53 PM, olcott wrote:

https://liarparadox.org/DD_correctly_simulated_by_HH_is_Proven.pdf
 At least 100 people kept denying the easily verified fact that the above
link conclusively proves that DD <is> correctly simulated by HH.
 It has been just like I smash a Boston cream pie in their face and they
persistently deny that there ever was any pie as this pie drips from
their face.
 

 The problem iks you use the WRONG DEFINITION of "Simulated Correctly" to allow the simulation to say anything about the behavior of the machine being simulated.
 

 *I conclusively proved otherwise in the above link*

 You CAN'T provd that a definition is wrong.
 

 *Try and provide a counter-example or implicitly admit that you cannot*
*Try and provide a counter-example or implicitly admit that you cannot*
*Try and provide a counter-example or implicitly admit that you cannot*

 What are you asking for a counter example of?
 

 The machine description of DD specifies that it does not halt to
simulating halt decider HH and you already know that you cannot
possibly prove otherwise.

 No, it specifies that it HALTS, since HH(DD,DD) will return 0.
 

 In other words you have always known that I am correct
that DD correctly simulated by HH CANNOT POSSIBLY HALT
and yet still try to get away with pure bluster.
 

 You are talking in circles and keep on changing topics, possible because you just don't know what you are talking about, or possible, your medication has made your brain too fuzzy.
 

 *It is a proven fact that directly executed DD(DD) has*
*different behavior than DD correctly simulated by HH*

It is self-evident from the meaning of the words and therefore
easily proven that a correct complete simulation of DD(DD)
reproduses the behaviour of DD(DD). Likewise it is self-evident
and therefore easily proven that a correct partial simulation
of DD(DD) reproduces a part of the the behaviour of DD(DD).
Of course, simulation of DD without an argument may do somenting
different.

*One can lie about this yet this lie is easily exposed*

Don't lie about that. Lying is not useful if easily exposed.
--
Mikko