Liste des Groupes | Revenir à s logic |
Op 28.jun.2024 om 20:31 schreef olcott:You can ignore the fact that DDD correctly simulated by HHHOn 6/28/2024 1:22 PM, Fred. Zwarts wrote:Change of subject ignored. This loop has more then two iterations. Why claiming falsehoods?Op 28.jun.2024 om 18:54 schreef olcott:>On 6/28/2024 10:48 AM, Fred. Zwarts wrote:>Op 28.jun.2024 om 17:32 schreef olcott:>>>
<MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
If simulating halt decider H correctly simulates its input D
until H correctly determines that its simulated D would never
stop running unless aborted then
>
H can abort its simulation of D and correctly report that D
specifies a non-halting sequence of configurations.
</MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
>
On 10/14/2022 7:44 PM, Ben Bacarisse wrote:
> I don't think that is the shell game. PO really /has/ an H
> (it's trivial to do for this one case) that correctly determines
> that P(P) *would* never stop running *unless* aborted.
>
>
But there is no correct simulation, so Sipser's approval does not apply.
The semantics of the x86 programming language specifies that
N steps of DDD were correctly emulated until the infinite
recursion behavior pattern was correctly matched.
What you say is that two equals infinite.
>
void Infinite_Loop()
{
HERE: goto HERE;
}
>
*In that case one = infinite*
>Yes, why do you?*We are not talking about infinite recursion. We are talking about a two cycle recursive simulation.*>
>>There is no infinite recursion pattern.
This has better color coding than the prior version.
https://liarparadox.org/HHH(DDD)_Full_Trace.pdf
>Let's agree about a two cycle recursive simulation, for which you have not shown any evidence that it can be done correctly.>
I have proven the verified fact that DDD is correctly emulated by
HHH and HHH correctly emulates itself emulating DDD until the outer
HHH sees that DDD meets the infinite recursion behavior pattern.
>
Sure there is. Why lie ?
>Change of subject ignored.
void Infinite_Recursion()
{
Infinite_Recursion();
}
Why distracting from the truth?
This is an example of infinite recursion. But we agreed to talk about two cycle recursion.
>So, you are unable to show any error in my reasoning.
_Infinite_Recursion()
[00002122] 55 push ebp
[00002123] 8bec mov ebp,esp
[00002125] e8f8ffffff call 00002122
[0000212a] 5d pop ebp
[0000212b] c3 ret
Size in bytes:(0010) [0000212b]
>
machine stack stack machine assembly
address address data code language
======== ======== ======== ========= =============
Begin Local Halt Decider Simulation Execution Trace Stored at:1138d2
[00002122][001138c2][001138c6] 55 push ebp
[00002123][001138c2][001138c6] 8bec mov ebp,esp
[00002125][001138be][0000212a] e8f8ffffff call 00002122
[00002122][001138ba][001138c2] 55 push ebp
[00002123][001138ba][001138c2] 8bec mov ebp,esp
[00002125][001138b6][0000212a] e8f8ffffff call 00002122
Local Halt Decider: Infinite Recursion Detected Simulation Stopped
>
>
>The simulated HHH runs one cycle behind the simulating HHH. The simulating HHH aborts the simulated HHH only one cycle before the simulated HHH would return.>
Aborting the simulation at this point makes it incorrect.
So, stop talking about infinite, because apparently do not understand what it means. Infinite is much more than two.
>
Les messages affichés proviennent d'usenet.