Re: Flat out dishonest or totally ignorant?

Op 02.jul.2024 om 21:00 schreef olcott:

On 7/2/2024 1:42 PM, Fred. Zwarts wrote:

Op 02.jul.2024 om 14:22 schreef olcott:

On 7/2/2024 3:22 AM, Fred. Zwarts wrote:

Op 02.jul.2024 om 03:25 schreef olcott:

typedef void (*ptr)();
int HHH(ptr P);
>
void Infinite_Loop()
{
   HERE: goto HERE;
}
>
void Infinite_Recursion()
{
   Infinite_Recursion();
}
>
void DDD()
{
   HHH(DDD);
}
>
int main()
{
   HHH(Infinite_Loop);
   HHH(Infinite_Recursion);
   HHH(DDD);
}
>
Every C programmer that knows what an x86 emulator is knows
that when HHH emulates the machine language of Infinite_Loop,
Infinite_Recursion, and DDD that it must abort these emulations
so that itself can terminate normally.

>
Whether or not it *must* abort is not very relevant.

>
This <is> the problem that I am willing to discuss.
I am unwilling to discuss any other problem.
This does meet the Sipser approved criteria.
>
<MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>
     If simulating halt decider H correctly simulates its input D
     until H correctly determines that its simulated D would never
     stop running unless aborted then
>
     H can abort its simulation of D and correctly report that D
     specifies a non-halting sequence of configurations.
</MIT Professor Sipser agreed to ONLY these verbatim words 10/13/2022>

>
Repeating the same thing that has already been proved to be irrelevant does not bring the discussion any further.
Sipser is not relevant, because that is about a correct simulation. Your simulation is not correct.
>

 If you disagree with this you are either dishonest
or clueless I no longer care which one.
 _DDD()
[00002172] 55               push ebp      ; housekeeping
[00002173] 8bec             mov ebp,esp   ; housekeeping
[00002175] 6872210000       push 00002172 ; push DDD
[0000217a] e853f4ffff       call 000015d2 ; call HHH(DDD)
[0000217f] 83c404           add esp,+04
[00002182] 5d               pop ebp
[00002183] c3               ret
Size in bytes:(0018) [00002183]
 DDD is correctly emulated by HHH which calls an
emulated HHH(DDD) to repeat the process until aborted.

HHH repeats the process twice and aborts too soon. One cycle later DDD would return, when the simulated HHH would have completed its own two cycles.
Therefore, HHH is incorrectly simulated by itself, because HHH aborts one cycle too soon and therefore misses the full behaviour of its simulated self, which aborts and returns, after which DDD returns.
You could not find any error in this reasoning, but you just ignore it and just repeat your baseless claim.
So, *you* are clueless and if you are not simply dishonest, your psychology is interesting. I have never met such a flat-out stubborn case.