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On 09.11.2024 15:03, Mikko wrote:Maybe, maybe not, depending on what is all n. If all n is all reals thenOn 2024-11-08 16:30:23 +0000, WM said:The measure of all intervals J(n) = [n - √2/10, n + √2/10] is smaller than 3.If Cantors enumeration of the rationals is complete, then all rationalsAll positive rationals quite obviously are in the sequence. Non-positive
are in the sequence 1/1, 1/2, 2/1, 1/3, 2/2, 3/1, 1/4, 2/3, 3/2, 4/1, 1/5, 2/4, 3/3, 4/2, 5/1, 1/6, 2/5, 3/4, 4/3, 5/2, 6/1, ... and none is outside.
rationals are not.
Therefore also irrational numbers cannot be there.That is equally obvious.
Of course this is wrong.You may call it wrong but that's the way they are.
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