Liste des Groupes | Revenir à s logic |
Glivenko is a basically RAA, reductio ad
absurdum shifted to the root. This is another
way to proof Glivenkos theorem.
I highly confused Joseph Vidal-Rosset on
SWI-Prolog discourse when I showed him
a intuitionistic prover that sometimes
also includes RAA, and then produces a classical
proof. RAA, reductio ad absurdum is this
inference rule:
G, ~A |- f
------------- (RAA)
G |- A
Compare this to Glivenko, basically double
negation elimiantion at the root:
???
---------------
G |- ~(~A)
--------------- (GLI)
G |- A
But what happens above G |- ~(~A), i.e. the
???? . By Gentzen inversion lemma, above
G |- ~(~A) we must find, G, ~A |- f,
and we are back to RAA:
G, ~A |- f
--------------- (R->) Gentzen inversion lemma
G |- ~(~A)
--------------- (GLI)
G |- A
So as much as Glivenko appears as a new alien
ivention, it has much to do with they age old
idea of "indirect proof".
Mild Shock schrieb:Its actually easier, you don't need to go
semantical. You need only to show that
Consequentia mirabilis aka Calvius Law
>
becomes admissible as an inference rule:
>
G, ~A |- A
---------------- (MIR)
G |- A
https://de.wikipedia.org/wiki/Consequentia_mirabilis
>
Which is a form of contraction. See also
>
Lectures on the Curry-Howard Isomorphism
6.6 The pure impicational fragment
https://shop.elsevier.com/books/lectures-on-the-curry-howard-isomorphism/sorensen/978-0-444-52077-7 >
>
The reason is that if you add MIR to
intuitionistic logic you get classical logic.
MIR is a very funny inference rule,
>
when you show it as an axiom schema:
>
((A -> f) -> A) -> A
>
Its a specialization of Peirce Law.
>
((P -> Q) -> P) -> P
>
Just set Q = f.
>
Julio Di Egidio schrieb:On 02/12/2024 09:31, Mild Shock wrote:>
>How does one usually demonstrate>
Glivenkos theorem?
Usually with a semantics: we have already said that up-thread...
>
-Julio
>
Les messages affichés proviennent d'usenet.