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Am Tue, 03 Dec 2024 12:10:53 +0100 schrieb WM:But for every segments more are needed: {1, 2, 3, ..., 10n}On 03.12.2024 11:03, Mikko wrote:Wow. For every segment there are numbers {10, 20, …, 10n}.
>I understand mathematicsHardly, though you may have the impression.
Proof: You cannot understand that the function f(10n) = n from D = {10n
| n ∈ ℕ} to ℕ = {1, 2, 3, ...} is not a bijection because for every
initial segment {1, 2, 3, ..., n} of ℕ there are too few numbers of the
form 10n that can be paired with numbers n.
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