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On 20/12/2024 02:48, Mild Shock wrote:Its quite intersting that Affine Logic canThough, can it? (More below.)
be measured by the realization of this output:
>
> - Output = Variable % Repetition
λx:A.λy:B.x : (A -> (B -> A))That is simply wrong, affine logic can of course prove a statement where, after the intros, hypothesis 1 is used once and hypothesis 2 is not used at all. That wouldn't be valid for linear logic (in the sense still of a substructural logic), as we are not using all hypothesis.
I tried it heuristically, Affine Logic can indeed not
prove (A -> (B -> A)). Don't know yet how to show it
rigorously, this would need some model theory.
As to how that relates to the lambda calculus side I still don't know, but I find significant that you says Repetition while I (substructural logic) says Use...
-Julio
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