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On 3/9/2025 2:24 PM, Richard Damon wrote:Note, he says to construct the antinomy of the liar in the METALANGUAGE representing the statement x in the LANGUAGE. Thus "x" is *NOT* the liar, but something that with the additional information of the metalanguage can be reduced to it.On 3/9/25 1:15 PM, olcott wrote:Tarski thought that is was undecidable and anchored hisIs the Liar Paradox True or False?>
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LP := ~True(LP)
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?- LP = not(true(LP)).
LP = not(true(LP)).
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?- unify_with_occurs_check(LP, not(true(LP))).
false.
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Its infinitely recursive structure makes it neither true nor false.
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The liar's paradox isn't an "undecidable" instance, as "undecidable" is about a problem that has a true or false answer that can not be computed for every case.
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whole proof in it.
Tarski's Liar Paradox from page 248
It would then be possible to reconstruct the antinomy of the liar
in the metalanguage, by forming in the language itself a sentence
x such that the sentence of the metalanguage which is correlated
with x asserts that x is not a true sentence.
https://liarparadox.org/Tarski_247_248.pdf
Formalized as:So? x is some sentence in the language, like say Godel's G that says there does not exist a number g such that g satisfies a particular primative recursive relationship.
x ∉ True if and only if p
where the symbol 'p' represents the whole sentence x
He never shows the above intermediate step beforeBecause he refers to the work he did earlier that shows it to be a valid transformation in the system.
he arbitrarily swaps True for Provable on line (1)
of his proof in the first paragraph of this proof.
(1) x ∉ Provable and only if pRight, so look at Theorem I
In accordance with the first part of Th. I
we can obtain the negation of one of the
sentences in condition (ex) of convention
T of § 3 as a consequence of the definition of
the symbol 'Pr' (provided we replace 'Tr' in
this convention by 'Pr').
https://liarparadox.org/Tarski_275_276.pdf
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