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On 27.05.2025 14:01, Mikko wrote:It does. Perhaps not good enough for all purposes but certainly goodOn 2025-05-26 13:38:00 +0000, WM said:That does not make this view good.
No alternative view is known to be better.
No, it is not. In order to use an inductive proof you must first specifyNo. All natural numbers can be manipulated collectively, for instance subtracted: ℕ \ {1, 2, 3, ...} = { }. Here all have disappeared.But even pure mathematics proves that most natural numbers will never be definable:(2) there are infinitely many (ℵo) possible definitions.
{1} has infinitely many (ℵo) successors.
Could all natural numbers be distinguished by individually defining each one, then this subtraction could also happen but, caused by the well-order, a last number would disappear.
It is a valid proof by induction. Claim it for all natural numbers. Get a contradiction. But perhaps you prefer geometry?If {1, 2, 3, ..., n} has infinitely many (ℵo) successors, then {1, 2, 3, ..., n, n+1} has infinitely many (ℵo) successors, for every n that can be defined.You can't formulate that as a logically or mathematically valid proof.
The set of finite initial segments of natural numbers is potentially infinite but not actually infinite.There is nothing potential in a set. If there are infinitely many members
(Actual infinity is a fixed number greater than all natural numbers.)Infinity is not a number but a feature some sets have and some don't.
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