Re: Does the number of nines increase?

Le 04/07/2024 à 13:00, joes a écrit :

Am Wed, 03 Jul 2024 20:05:48 +0000 schrieb WM:
>

so dass n < m < ω gilt.

For every visible natural number this is true.

There is no such thing as „visibility”.

There is invisibility: For all visible/choosable n: |ℕ \ {1, 2, 3, ..., n}| = ℵo.

 

Like ∀x > 0: NUF(x) = ℵo is true. But this truth proves the existence of
dark numbers, because between every such x and 0 there must lie ℵo unit
fractions and ℵo finite distances between them.

Why? That distance can be divided infinitely.

But the first unit fraction already is an x > 0.
Regards, WM