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On 11.02.2025 18:42, Jim Burns wrote:On 2/11/2025 4:31 AM, WM wrote:
What is this "both proofs"?>The set F of FISONs which can be removed>
without changing the assumed result UF = ℕ
is the infinite set F of all FISONs.
Yes.
Fine.
>This is proven by just the same induction
as Zermelo proves his infinite set Z.
>
Either you accept both proofs or none.
There is no further step.
>But without there is no set theory.>
That part above is fine.
Your problem is in the step after that,
which, for some reason, you skip over.
The part above defines
the set of all FISONs that can be omitted
without changing the union.
There is no further step.Then there is no further conclusion.
ThenOnly a hypothetical last.FISON ͚F,>
a FISON with {after.͚F} = {}
supports your reasoning:
The set of all FISONs is accepted.
No further restricitons allowed.
No.There is no last FISON.>
⋃{} ≠ ℕ
That is not claimed.
Claimed is only UF = ℕ ==> ⋃{} = ℕ.What is your new reason for claiming UF = U{} ?
Can't you understand the meaning of an implication?You (WM) currently are ignoring that,
>>No, I won't try to dive into your private notation.>
Do you accept that,
for each two FISON.numbers j′ and i′
there exists a FISON.number maximum k′ of
i′ and the successor j′+1 of j′
?
It is irrelevant what details exist.
Induction covers the whole infinite set.
>How induction works is not well known to you (WM).>
What is wrong in my application in your opinion?
Induction covers the whole infinite set.You mean by that
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