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On 20.10.2024 00:54, Jim Burns wrote:But since there isn't a "largest" number, we can find that in the set.On 10/19/2024 2:19 PM, WM wrote:A doubled finite is finite.If all finites are doubled, then not all results can be in that set.
Either more finites appear, or the results are infinite.>All doubled numbers result in larger numbers. That cannot be avoided.
No k exists such that
2⋅k is a finite and 2⋅k+2 > 2⋅k is not a finite.
Regards, WM
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