Re: Incompleteness of Cantor's enumeration of the rational numbers (extra-ordinary)

On 12/7/24 5:44 AM, WM wrote:

On 06.12.2024 14:30, joes wrote:

Am Thu, 05 Dec 2024 17:04:58 +0100 schrieb WM:

On 05.12.2024 13:56, joes wrote:

Am Thu, 05 Dec 2024 12:42:17 +0100 schrieb WM:

>

But every number you can take belongs to a vanishing subset of ℕ.

What does that have to do with the ability to be "chosen"?

It is impossible to choose a number outside of a tiny subset.

Duh. There are no other numbers.

 May be. My statements however concern completed infinity. The subset is never complete.
 Regards, WM
 

And thus the limit of the subsets is not complete either, per your logic of a limit of constants is always that same constant. Thus, your trying to define the complete infinity just fails.