Re: 2N=E

On 10/28/2024 4:01 PM, WM wrote:

On 28.10.2024 13:23, Jim Burns wrote:

On 10/26/2024 11:55 AM, WM wrote:

On 26.10.2024 01:18, Jim Burns wrote:

On 10/25/2024 3:07 PM, WM wrote:

Relevant are only provable mathematical facts:

>
Provable:
⟦0,n⟧ ⊂ ⟦0,ω⦆  ⇔  ⟦0,n+n⟧ ⊂ ⟦0,ω⦆

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True for all natnumbers you can conceive of.

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True for all finite ordinal which are finite ordinals.

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Relevant is only that
the density in the interval is halved,
the number remains,
the interval is doubled.

For each finite ordinal n
there is a larger finite double n+n
For each finite double n+n
there is a larger finite ordinal n+n+1
The finite ordinal interval and
the finite double interval are the same.
'Infinite' does not mean what you want it to mean.