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On 12/5/2024 4:00 AM, WM wrote:And it is the empty endsegment. The contents cannot disappear "in the limit". It has to be lost one by one if ∀k ∈ ℕ : E(k+1) = E(k) \ {k} is really true for all natnumbers.On 04.12.2024 21:36, Jim Burns wrote:On 12/4/2024 12:29 PM, WM wrote:⎛ That's the intersection.>[...]>
No intersection of
more.than.finitely.many end.segments
of the finite.cardinals
holds a finite.cardinal, or
is non.empty.
Small wonder.
More than finitely many endsegments
require
infinitely many indices, i.e., all indices.
No natnumbers are remaining in the contents.
⎜
That means an empty endsegment and many having finite contents.Small wonder.Yes.
More than finitely many endsegments
require
infinitely many indices, i.e., all indices.
No natnumbers are remaining in the contents.
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