Re: More complex numbers than reals?

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Sujet : Re: More complex numbers than reals?
De : noreply (at) *nospam* example.org (joes)
Groupes : sci.math
Date : 15. Jul 2024, 14:41:59
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Organisation : i2pn2 (i2pn.org)
Message-ID : <3bcdc0e737dc23dca26ae5c0f854210a2909cf15@i2pn2.org>
References : 1 2 3 4 5 6 7 8 9 10 11
User-Agent : Pan/0.145 (Duplicitous mercenary valetism; d7e168a git.gnome.org/pan2)
Am Mon, 15 Jul 2024 13:26:25 +0000 schrieb WM:
Le 15/07/2024 à 00:39, Ben Bacarisse a écrit :
WM <wolfgang.mueckenheim@tha.de> writes:
 
You can define equinumerosity any way you like.
And I can prove that Cantor's way leads astray.
But no journal will touch it.  I can't remember which crank excuse you
use to explain that.
Simple: The journals are owned by matheologians and stupids. I have
never tried to address them.
Further all that stuff including this proof has been published as a
book.
Standing in the face of the establishment is a sure sign of a crackpot.

Presumably that's why you teach history courses now -- you can avoid
having to write down even the most basic definitions of WMaths sets.
At the end of the course I talk about the present state of the art.
Do you cite the journal that has published your proof that Cantor is
wrong?
"Does Set Theory Cause Perceptual Problems?", viXra 2017-02-26
"Transfinity - A Source Book", SSRN-Elsevier (April 2024)
"Proof of the existence of dark numbers (bilingual version)",
OSFPREPRINTS (Nov 2022)
"Dark numbers", Academia.edu (2020)
"Dark numbers", Quora (May 2023)
"Sequences and Limits", Advances in Pure Mathematics 5, 2015, pp. 59 -
61.
"Transfinity - A Source Book", ELIVA Press, Chisinau 2024.
Cutting down to different platforms, I see only one book and one article.
The others count as selfpublished and haha, quora.

Do you give the "proper" definitions for set membership,
That cannot be done for potentially infinite collections because they
have no fixed membership.
And that is why no one uses it.

difference and equality once you admit that those in your textbook are
only approximations?  Do you present a proof of the "surprising" result
that sets E and P exist with E in P and P \ {E} = P?
There has not yet been any disprove of my simplest proof (that I told
you recently and that you were wise enaugh to let it uncommented). The
only daredevil who tried it, Jim Burns, has to assume that by exchangig
one of the elements can disappear. No reason to pay attention. And the
nonsense you once tried to sell to my former students has been rejected
by them flatly.
Oh really? What do your students say?

--
Am Fri, 28 Jun 2024 16:52:17 -0500 schrieb olcott:
Objectively I am a genius.

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