Sujet : Re: Does the number of nines increase?
De : noreply (at) *nospam* example.org (joes)
Groupes : sci.mathDate : 08. Jul 2024, 21:44:11
Autres entêtes
Organisation : i2pn2 (i2pn.org)
Message-ID : <72984017b5af15267bdcd281564efdd028083003@i2pn2.org>
References : 1 2 3 4 5 6 7 8 9 10 11
User-Agent : Pan/0.145 (Duplicitous mercenary valetism; d7e168a git.gnome.org/pan2)
Am Mon, 08 Jul 2024 19:57:33 +0000 schrieb WM:
Le 08/07/2024 à 19:33, Jim Burns a écrit :
On 7/8/2024 9:49 AM, WM wrote:
There is no point x > 0: NUF(x) < ℵ₀
That is wrong because 10 unit fractions and their finite distances
occupy a part of the positive axis which has a finite positive measure.
Therefore there exist x > 0: NUF(x) < 11. in order to accumulate ℵ₀ unit
fractions, at least 10 must exist at the beginning. Are you unable to
understand that?
Which ten.
There is no point x < 0: NUF(x) > 0 NUF(x) changes "at" 0.
The function f(x) = [x] changes at 1 from 0 to 1, at 2 from 1 to 2, and
so on.
The function NUF(x) changes at unit fractions by 1, but not before, not
at 0.
NUF changes at 0 from 0 to omega.
Therefore it does not change at 0.
Functions do not change at single points.
You are wrong. The function f(x) = [x] changes at the points 1, 2, 3,
...
And NUF changes like the sign function.
-- Am Fri, 28 Jun 2024 16:52:17 -0500 schrieb olcott:Objectively I am a genius.